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What is the percentage increase in length and breadth of rectangle?

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What is the percentage increase in length and breadth of rectangle?

For a rectangle, the length and breadth are increased by 10\% and 20\%, respectively. What is the percentage increase in area? – Quora For a rectangle, the length and breadth are increased by 10\% and 20\%, respectively.

What is the increase in area of the second RECTANGLE?

Its area = 220*108 = 23760 sq cm. Hence the increase in area of the second to the first rectangle is [23760–20000]*100/20000 = 3760*100/20000 = 18.8\%. Let length & breadth of a rectangle be L & B respectively. Hence Area of rectangle will be increased by 18\%.

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How do you calculate the percentage increase in perimeter of a rectangle?

Percentage increase in perimeter = (10×3 + 15×2)/ (3+2) = 12\%. Answer. the perimeter original was 2l + 2b, l= length, b= breadth of this rectangle. increase in perimeter is 2×10\% of l + 2x 15\% of breadth=0.2l+0.3b. = 50 (0.2l+0.3b)/ (l+b). me thinks it’s it. Should I hire remote software developers from Turing.com?

What is the percentage increase in length from 10 to 8?

If you have length and breath both at 100 percent of their initial size, the percentage result of adding 10 and 8 percent would increase the area by (110* 1,08) – 100. The result is an increase of 18,8 percent. Early symptoms of spinal muscular atrophy may surprise you.

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What is the area of the larger rectangle?

The area of a rectangle is given by L*B (where L = length and B = breadth). So, the original rectangle and length x and breadth y, its area would be xy. The larger rectangle would have area 1.1x*1.1y = 1.21 xy. So, it is increased by 21\%.

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How do you calculate the area of a derease in length?

An increase of 20\% in length would increase the area by 20percent. Now a derease in breadth by 10\% would decrease the area by 10\% Therefore new area = 120 – (10\% 0f 120) = 120 – 12 = 108

What is the area of the rectangle if the length is increased?

If the length of a rectangular field is increased by 20\% and the breadth is reduced by 20\%. The area of the rectangle will be 192 m². What is the area of the original rectangle? , B.tech Electrical Engineering, Dr.Babasaheb Ambedkar Technological University, Lonere Raigad Maharashtra (201… The length of a rectangle is increased by 10\%.

What is the area decreased by 10\% when length increases?

For area to remain same ΔA/A should be equal to zero. (Given length increases by 10\%, that means x = 0.1) Given that, area is same in both case. therefore, approx 9\% of breadth is decreased to constant the area. How did this girl break the private jet industry with just $250?

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