How many numbers between 100 and 1000 can be formed with the digits?

Hence the total number lying between 100 and 1000 which can be formed with digits 0, 1, 2, 3, 4, 5, 6, 7 are 294 numbers i.e. \[{}^{8}{{P}_{3}}-{}^{7}{{P}_{2}}\].

How many numbers can be formed using the digits 1,2 3 without repetition?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.

How many 3 digits numbers can be formed if the repetition of digits is not allowed?

As repetition is not allowed, So the number of digits available for Y = 4 (As one digit has already been chosen at X), Similarly, the number of digits available for Z = 3. Thus, The total number of 3-digit numbers that can be formed = 5×4×3 = 60.

How many numbers can be formed using all of the digits 1/2 and 3 exactly once?

Originally Answered: How many 3-digit numbers can be formed using only1, 2, 3? This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .

How many numbers between 1000 and 10000 can be formed with the digit 123456?

Therefore, we get the required answer as 3024. Hence, there are 3024 numbers which can be formed between 1000 and 10000 using 1,2,…. 9. Hence, option A is the correct answer.

How many ways can a 3 digit numbers be formed using 1 2 3 and 4 without repetition?

So the number of 3-number combinations are- (1,2,3),(1,2,4),(1,3,4),(2,3,4). Each can be arranged in 6 ways, so we get 24 ways totally.

How many ways the three digits 1/2 and 3 can be arranged if repetition is allowed?

The first digit of the 3-digits can take 7 distinct values: 1, 2, 3, 4, 5, 7, 9. As repetition is allowed, the second digit can also take 7 distinct values, and the third can take 7 distinct values aswell, giving a total of 7⋅7⋅7=343 distinct combinations of numbers.

How many 3 digit numbers can be written from the digits 1 2 3 and 4 if repetition of digits is allowed?

How many numbers can be formed by using all the digits 1 2 3 4 3 2 1 so that the odd digits always occupy the odd places?

Answer Expert Verified We can form 7 digits numbers.

How many 3 digit numbers are there between 200 and 1200?

Only possible 4 digit numbers are 1023 and 1032 i.e. only 2 numbers. So total of 14 numbers (without repetition) between 200 & 1200 with 0, 1, 2 & 3. 3 digit numbers = 2*4*4=32.

How many 2 digit numbers are there in all?

1 The smallest 2-digit number is 10 and the greatest 2-digit number is 99. 2 There are 90 2-digit numbers in all. 3 1 tens is equal to 10. 4 A 2-digit number cannot start with 0, because in that case it will be considered as a single-digit number.

How many ways can a 5-digit number be filled up?

A five-digit number cannot have 0 as the first digit on the left, which is the ten thousand place. Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways.

How do you choose the first two digits of 012?

There are nine possible first digits, because numbers beginning in 0 drop the 0, so 012 is really just 12, a two digit number. The first digit must be 1 thru 9, nine possible digits. The second digit can be any of the nine digits left after you take the first digit out of the pool of choices. So 9*9 ways to chose the first two digits.