How many times does 3 occur in the hundreds place in the number between 100 and 10000?

The digit “3” occurs 3980 times in all numbers from 100 to 10,000.

How many times does the digit 3 occur between 1 and 100?

Numbers from 1 to 100 in which 3 is coming at unit place are 3, 13, 23, 33, 43, 53, 63, 73, 83, 93. Hence, total numbers are 10.

How many times does the digit 3 occur in the hundreds place?

B can take values 0 to 9, C can take values 0 to 9, D can take values 0 to 9. So, 3 gets printed in the 100’s place 1000 times.

How many times does digit 3 occur in tens place in the whole numbers from 100 to 1000?

Answer: 3 occurs 90 times in tens and 90 times in the unit place in the numbers from 100 to 1000.

How many times does digit 3 occur?

The only three digit number that has 3 in all places is 333. Therefore, the number of three digit numbers having the digit 3 in all places is 1. Here, the digit 3 comes thrice. Therefore, the number of times 3 appears is 3.

How many times the digit 3 occurs in the tens place in the numbers from 20 to 800?

It occurs 80 times.

How many times does the digit 3 appear between 1 and 100 such that the numbers where 3 appears is not divisible by 3?

Multiples of 3 with 1 to 33 are from 3 to 99. In other words from 3 to 99 there are 66 numbers which cant be divided by 3. with this 66, add another three digits, corresponding to 1 , 2 and 100. Hence , there are 69 numbers , between 1 to 100 & not divisible by 3 .

How many 3 are there in a 100?

Twenty. In the ones position, there are 10 instances (3, 13, 23, 33, 43, 53, 63, 73, 83, 93). In the tens position, there are also 10 instances (30, 31, 32, 33, 34, 35, 36, 37, 38, 39).

How many times does the digit 3 appear between 1 and 100 such that the number 13 appears is not divisible by 3?

Hence , there are 69 numbers , between 1 to 100 & not divisible by 3 .

How many times does the digit 5 occurs in tens place in the natural numbers from 100 to 1000?

Answer: Hence, the digit 5 appears 271 times from 1 to 1000.

How many times does the digit 3 appear in numbers from 1 to 100 such that the numbers where 3 appears is not divisible by 3?

Solution(By Examveda Team) Clearly, from 1 to 100, there are ten numbers with 3 as the unit’s digit- 3, 13, 23, 33, 43, 53, 63, 73, 83, 93; and ten numbers with 3 as the ten’s digit – 30, 31, 32, 33, 34, 35, 36, 37, 38, 39. So, required number = 10 + 10 = 20.

How many times does the digit 3 appear between 1 and 100 such that the number where three appears is not divisible by 3?

How many times does the digit 3 appear in 1 to 1000?

To be SUPER “nitpicky,” the digit 3, appears INFINITELY MANY TIMES in 1 to 1000. Since the question doesn’t say that we’re dealing with INTEGERS, we can even say that the digit 3 appears INFINITELY MANY TIMES in the (rational) numbers from 1 to 2. How many times does the digit 3 appear in the integers from 1 to 1000 inclusive?

How many 3s are there in a 10 digit integer?

There are 3 digits in each integer. Each of the 10 digits is equally represented, so the 3 will account for 1/10 of all digits. Just a quick question. From 1 to 1000, we will have 33, 333. So these will be counted one 3 or more than one 3?

What are the numbers in which 3 occurs only once?

The numbers in which 3 occurs only once. This means that 3 is one of the digits and the remaining two digits will be any of the other 9 digits You have 1*9*9 = 81 such numbers. However, 3 could appear as the first or the second or the third digit.

How many digits are there in the integers from 000 to 999?

First, there are 1000 integers from 000 to 999 There are 3 digits in each integer. So, there is a TOTAL of 3000 individual digit. (since 1000 x 3 = 3000) Each of the 10 digits is equally represented, so the 3 will account for 1/10 of all digits.