What happens to the force between two electric charges if the distance between them is halved?

Explanation: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.

How does the Coulomb force between the two point charges vary with the distance of separation between them?

Answer: The electrical force between two charged objects is inversely related to the distance of separation between the two objects. So if distance increases 2 times, force reduces 4 times.

What happens to the electric force between two charges when the distance is doubled and tripled?

4. Two charged objects have a repulsive force of 0.080 N. If the distance separating the objects is tripled, then what is the new force? Explanation: The electrostatic force is inversely related to the square of the separation distance….Inverse Square Law.

Row	Separation Distance	Electrostatic Force
5	100.0 cm	0.0051 N

When the distance between the two charges as well as their magnitude is decreased to half then the force between them is?

quadrupled
If the distance between two charges is reduced by half then the force between the two charges is quadrupled.

What happens to gravitational force when distance is halved?

When distance between objects is halved, gravitational force becomes four times. When distance between objects is doubled, gravitational force becomes one-fourth.

What would happen to the force experienced by two charges if the distance between them became 3 times greater?

Explanation: The electrostatic force is inversely related to the square of the separation distance. So if d is three times larger, then F is nine times smaller – that is, one-ninth the original value.

When the distance between the charges increases by a factor of 4 the Coulomb force between the charges?

Force is inversely proportional to the square of the distance between the charges. Therefore, if the distance increases by a factor of 2, the force decreases by a factor of 4.

What happens if the distance between two charges is doubled?

If the distance between two charges is doubled, what will happen the force between the charges? the force between 2 charges, by coulomb’s law is given by, F = q1q2 4πε0r2 where, q1 and q2 are the magnitude of the charges. and r is the distance between them.

What is the force acting on the same charges if halved?

From Coloumb’s law of electrostatic force we know, F = kq1q2 r2 (where, k is a constant, q1 and q2 are two charges separated by distance r) So,if the distance between the charges is halved, with no changes of the charges,new distance becomes r 2 So,if now force acting between the same charges is F

What is the effect of magnitude doubled on force?

Magnitude doubled, it means force increased by 4 times. Because charges are 2 in magnitude and when it get doubled this becomes four times. Next is the effect of distance on force which inverse relation. When distance gets half force becomes double. As distance is of square so, it would increse 4 times.

Why does force increase 4 times as distance is doubled?

Because charges are 2 in magnitude and when it get doubled this becomes four times. Next is the effect of distance on force which inverse relation. When distance gets half force becomes double. As distance is of square so, it would increse 4 times. F= 1/r2= 1/ (2) square= 1/4, force increase 4 times as distance gets doubled.