What is the empirical formula of Sulphur oxide which contains 50\% by mass Sulphur?
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What is the empirical formula of Sulphur oxide which contains 50\% by mass Sulphur?
SO2
Its empirical formula is : For sulphur, the percentage of sulphur divided by its molar mass gives = 50/32=1.56 For oxygen, the percentage of sulphur divided by its molar mass = 50/16= 3.12 It is clear that it is in 1:2 ratio. Hence, the emperial formula is SO2.
What is the formula of sulfur oxide?
Sulfur oxide
| PubChem CID | 114845 |
|---|---|
| Structure | Find Similar Structures |
| Molecular Formula | OS |
| Synonyms | Sulfur monoxide Sulfur oxide 13827-32-2 SO Sulfur oxide (SO) More… |
| Molecular Weight | 48.07 |
What is the empirical formula of a compound that is 50\% carbon and 50\% oxygen?
C4O3
A compound has 50\% carbon, 50\% oxygen and approximate molecular we | Filo. Solution: Elements Simple ratio C=5050/12=4 (CH2O) Empirical formula = C4O3 Empirical formula mass = 96 n=29096=3 Molecular formula = (C4O3)3=C12O9.
What is the empirical formula for sulfur?
SF6
The molar mass of sulfur = 32.065g/mol . The molar mass of fluorine = 18.9984032g/mol . Divide the number of moles by the lowest number of moles to find the lowest whole-number ratio. The empirical formula is SF6 .
What is the empirical formula of an oxide of element containing 40 element by mass?
So, Empirical Formula is EO3.
What is the atomic mass of Sulphur?
32.065 u
Sulfur/Atomic mass
What is the molecular mass of Sulphur dioxide?
64.066 g/mol
Sulfur dioxide/Molar mass
What is the molecular mass of sulfur?
What is the empirical formula of a compound that contains 50\% carbon 6.7\% hydrogen and 43.3\% oxygen by mass?
We divide thru by the lowest molar quantity, that of oxygen to get a formula of C1.54H2.45O1 , which we double to give a whole number EMPIRICAL formula of C3H5O2 .
What is the empirical formula of a compound that is 40\% sulfur by mass and 60\% oxygen by mass?
Moles Review
| Question | Answer |
|---|---|
| What is the molar mass of Li3(PO3)? | 99.79g |
| What is the empirical formula of a compound that is 40\% sulfur and 60\% oxygen by weight? | SO3 |
| What is the empirical formula of a substance that is 53.5\%C,15.5\%H,and 31.1\%N by weight? | C2H7N |
| How many particles are in 3.54 moles of NH3? | 2.131×10^24 particles |
What is the empirical formula of an oxide of element?
We already know the percentage and atomic weight so we calculate the atomic ratio and then using atomic ratios we calculate the simplest ratios. The ratios should not be in decimal and must be in whole numbers. Hence the Empirical formula of the oxide will be $E{O_3}$ . Hence option (3) is correct.