Common questions

What is the least number of 6 digit which is exactly divisible by 111?

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What is the least number of 6 digit which is exactly divisible by 111?

100011
So, the answer to this question is 100011. This means that the smallest six – digit number that is completely divisible by 111 is 100011.

What is the least 4 digit number divisible by 13?

Step-by-step explanation: The last 4-digit number divisible by 13 is 9997.

Which is the smallest 6 digit number exactly divisible by 18?

Hint: Let l be the LCM (a,b,c). Then ∀n such that a|n,b|n and c|n⇒l|n . Hence first find the LCM of 18,24 and 30. Then find the smallest six digit multiple of the LCM and hence the number obtained will be the smallest six-digit number divisible by 18, 24 and 20.

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What is the least 6 digits divisible by 739?

The smallest six digits number divisible by 739 is 739 × 136 = 100504 ans.

What is the least 6 digit number exactly divisible by 83?

So, 100015 is the least six-digit number exactly divisible by 83.

Is there a divisibility rule for 13?

Divisibility Rule. If adding four times the last digit to the number formed by remaining digits is divisible by 13, then the number is divisible by 13. Apart from 13, there are divisibility rules for 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, and so on.

What is the least number of 4 digits exactly?

The smallest number of 4 digits is 1000.

What is the least 6 digit number divisible by 71?

Detailed Solution. Smallest 6-digit number is 100000. When, 100000 is divided by 71 we get a remainder of 32.

What is the least 6 digit number divisible by 83?

In order to find the least 6-digit number exactly divisible by 83, we have to add 83 − 68 = 15 to the dividend. So, 100015 is the least six-digit number exactly divisible by 83.

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How to prove that a number is divisible by 13?

In any n digit number ,If the difference between the number formed by last three digit and rest of digit of the is divisible by 13 then the number is divisible 13 .

What is the easiest way to memorize divisibility of 13?

That’s the easiest. Or you can memorize the decimal forms of 1 / 13, 2 / 13, etc, up to any number of decimals if you are set on knowing in your head. In any n digit number ,If the difference between the number formed by last three digit and rest of digit of the is divisible by 13 then the number is divisible 13 .

Is 1234 divisible by 13?

So 1234 is not divisible by 13 (otherwise it would be = 0 (mod 13)). For another example take 5678. Skipping a few steps above we get: So 5678 is also not divisible by 13. With practice this approach could be an effective way to check for divisibility by 13. But for most people it would be faster and easier to just do the long division.

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What is the remainder when dividing 13 using powers of ten?

The one for 13 is based on the decimal decomposition of a number. For instance you can write 1234 in terms of powers of ten as follows: Any four-digit number can be expressed this way. Now if you memorize what , and are equivalent to mod 13 you can use that to compute the remainder when dividing by 13. Specifically: