Other

What is the perimeter of 12?

by Author

What is the perimeter of 12?

If a square has an area of 9 square inches, each side is 3 inches. This is because 3 inches times 3 inches is 9 inches. (The formula for the area of a square is length times hieght.) Given that a square has 4 sides, we get the perimeter by multiplying 3 by 4, giving us a perimeter of 12 inches.

What is the perimeter of a 12 in square?

If the perimeter of a square is 12 feet, then the length of a side is 12/4 = 3 feet.

What is the area of a 12 square?

12² = 144. Extending that, if you say “12 inches squared,” it’s a logical process to square 12 inches, giving us 144 inches. So “12 inches squared” is a long distance of 144 inches and “12 square inches” is a 3 by 4 inch area. Or 2 by 6.

READ:   How does Google Maps know real time traffic?

How to calculate the length and width of a rectangle?

Online calculator to calculate the dimensions (length and width) of a rectangle given the area A and perimeter P of the rectangle. The formulas for the perimeter P and the area A of the rectangle are used to write equations as follows: P = 2 * L + 2 * W A = L * W

What is the formula for the perimeter of a rectangle?

Perimeter of a rectangle formula. The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition.

What is the unit of area of a rectangle?

In other words, the area of a rectangle is the product of its length and width. The perimeter is measured in units such as centimeters, meters, kilometers, inches, feet, yards, and miles. The area is measured in units units such as square centimeters (cm2) ( c m 2), square meters (m2) ( m 2), square kilometers (km2) ( k m 2) etc.

READ:   Is Instacart cheaper if you pick up?

What are the outputs of the rectangle problem?

The outputs are the width, length and diagonal of the rectangle. There are conditions under which this problem has a solution (see formulation of problem below). Let P be the perimeter of a rectangle and A its area. Let W and L be, respectively, the width and length of the rectangle.