What is the range of 3sinx 4cosx?

Hence the range is [−10, 0].

What is the maximum and minimum value of 3sinx 4cosx?

For calculating the maximum and minimum value of a trigonometric equation we can use this formula. Condition: The Equation must be of the form: a Cos x + b Sin x. Hence the minimum value of the function is -5.

What is the maximum value of 2 3sinx 4cosx?

Max value is 7. So at this point the graph is concave down, therefore proven max.

What is the range of 7cosx 24sinx 5?

so, range is -20 and 30.

What is the maximum value of 3cosx 4sinx 5?

Therefore, the maximum value is 10.

How do you prove sin3x 3sinx 4sin 3x?

1 Answer

1. sin 3x = sin(2x + x)
2. = sin 2xcosx + cos2x sin x.
3. = 2sin xcosxcosx + (1 – 2sin2x)sin x.
4. = 2 sin x(1- sin2 x) + sin x – 2 sin3 x.
5. = 3sinx – 4sin3x.

What is the minimum value of 3cosx 4sinx?

0
Therefore, the minimum value of 3 cos x + 4 sin x + 5 is 0.

Is sin3X 3Sinx?

But leaving x = nπ, sin3X can almost almost equal to 3Sinx, making (sinx)^3 = 0. As a cubic function has downward concavity and sinx has upward concavity. So the smaller x coordinates for sin^3 will give nearly zero value. And can be ignored.

How do you prove sin3X?

The expansion of sin 3x formula can be derived using the angle addition identity of the sine function….We will use the following trigonometric identities to prove the sin 3x identity:

1. sin (a + b) = sin a cos b + cos a sin b.
2. sin 2x = 2 sin x cos x.
3. cos 2x = 1 – 2sin2x.
4. sin2x + cos2x = 1.

What is the maximum and minimum value of sinx COSX?

a*sinx + b*cosx, maximum & minimum value is (+,-)√[a^2+b^2]. As here a=b=1, maximum and minimum value of sinx + cosx = (+,-)√[1^2+1^2], i.e. +√2 is maximum value and -√2 is the minimum value.

What is the range of 3sinx-4cosx?

To determine the range of 3sinx-4cosx, we should look at the four min/max points of cos and sin between 0 and 2pi. At x = 0, 3sin (0) – 4cos (0) = -4 So the expression 3sinx-4cosx has a range of [-4,4].

What is the maximum value of f(x) = (3 sin x – 4 cosx – 10)?

The maximum value of f (x) = (3 sin x − 4 cos x − 10)(3 sin x + 4 cos x − 10) is? f (x) will be maximum when (5sinx − 6)2 is maximum . It will be possible for sinx = − 1

What are the maximum and minimum values of the function ‘asinx+bcosx’?

Maximum and minimum values of the function type ‘asinx+bcosx’ is from – (a^2+b^2)^1/2 to (a^2+b^2)^1/2. Hence the answer is -5 to +5.

What is the value of sin t = 4/5?

(acosx + bsinx) is given by √ (a^2+b^2). Let 3=a cos t and 4=a sin t or tan t = 4/3. From the given eq. we get f (x) = a sin (x+t) We have tan t = 4/3 and from this we get sin t = 4/5.