What is the velocity and acceleration of the particle after 2 seconds?

Ans: The velocity and acceleration of the particle after 2 seconds are – 9 units/s and 4 units/s 2 respectively. A particle is moving in such a way that is displacement’s’ at any time ‘t’ is given by s = 2t3 – 5t2 + 4t – 3.

Is the velocity a differentiable function of time t?

The data in the table gives selected values for tbe velocity, in meters per minute, of a particle moving along the x-axis. The velocity is a differentiable function of time t. Velocity At t 0, is the paaticle moving to the right or left? 12 Is there a time during the time interval 0 t 12 minutes When the particle is at rest?

Are the velocities at T = 1 and T = 9 equal?

We can seet hat the velocities at t = 1 and t =9 are equal in magnitude and opposite in direction. (Proved) A particle is moving in a straight line and its displacement x from a fixed point O on the line at time t is given by .

What is the velocity function for a particle moving along a line?

The velocity function is v(t) = – t2 + 3t– 2 for a particle moving along a line. What is the displacement (net distance covered) of the particle during the time interval [-3,6]?

How do you find displacement from velocity function?

To find the displacement (position shift) from the velocity function, we just integrate the function. The negative areas below the x-axis subtract from the total displacement. Displacement = To find the distance traveled we have to use absolute value.

What is the acceleration in MS^-2 at time t2?

A point moves in a straight line so that its displacement x metre at time t second is given by x^2 = 1 + t^2 . Its acceleration in ms^-2 at time t second is > A point moves in a straight…

How do you find the position of a particle in time?

A particle moves along the x-axis so that at time t its position is given by — t 3 _ 6t2 11 x(t) — where t is measured in seconds and x is measured in feet. a. Att = 0, is the particle moving to the right b. Att = 1, is the velocity of the particle or left?

What is the maximum acceleration of a particle with displacement 12 cm?

A particle performing S.H.M. along a straight line has a velocity of 4π cm/s when its displacement is √12 cm. If the maximum acceleration it can attain is 16π2 cm/s2, find the amplitude and the period of its oscillations.

What is the maximum velocity of a particle executing SHM?

A particle executing S.H.M. has a maximum velocity of 0.16 cm/s and a maximum acceleration of 0.64 m/s2. Calculate its amplitude and the period of oscillations. Given: vmax = 0.16 cm/s, f max = 0.64 m/s 2.

How do you calculate final velocity from acceleration and initial velocity?

Velocity Equation in these calculations: Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. v=u+at. Where: u = initial velocity.