Which is the smallest number leaving a remainder 1 on division by 5 6 7 and 8?

Therefore, the least number is 1683. Hope it helps!

What is the smallest number that has a remainder of one when divided by 2 3 4 5 and 6?

Step 1- Find out the LCM of 2, 3, 4, 5, 6 which is 60. Step 2- Add 1 to 60 which is 61. Step 3- Multiple 61 by 7 repeatedly till it fulfills the condition that remainder should be 1. Step 4- I got the answer 146461 which seems to correct.

What is the smallest number which when divided by 3 4 5 6 7 leaves a remainder 2?

62 is the smallest number which gives 2 as reminder when divided by 3, 4, 5 and 6.

What is the smallest number that can be divided by 6 and 7 with a remainder of 4?

LCM of 4, 6 and 7 is 84. So, the smallest number leaving remainder 2 will be 86.

What is least number which when divided by 5 6 7 and 8 leaves a remainder 3 but when divided by 9 leaves no remainder?

Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

What is the smallest number which when divided by 6 and 8 leaves remainder 5?

We can easily find the L.C.M of given integers simply by using the prime factorization method. L.C.M of 6, 8, 12, 15, 20 \[ = 2 \times 2 \times 2 \times 3 \times 5\]=120. 120 is the smallest number which will completely divide the numbers (6, 8, 12, 15, 20). Since, we want remainder 5.

What is the smallest number that leaves a remainder of 1 when divided by 2 or 5 or 6?

The answer is 11. When divided by 2 it gives 5, remainder 1; when divided by 3 it gives 3, remainder 2; and when divided by 4 it give 2, remainder 3. Note that the answer must be an odd number, since when divided by 2 it leaves a remainder of 1. So 3, 5, 7, 9, 11, etc.

What is the smallest positive number that leaves a remainder of 2?

It’s 60 . That’s it. The smallest number that keeps leaving a remainder of two just as we want is 62 , and so the answer to the problem is (B).

What is the smallest number that leaves a remainder of 4?

Answers and Solutions Question: Find the smallest number that leaves a remainder of 4 on division by 5, 5 on division by 6, 6 on division by 7, 7 on division by 8 and 8 on division by 9? Answer: LCM (5, 6, 7, 8, 9) – 1 = 2519.

What is the least number which leaves remainder 3 and 7 respectively when divided by 7 and 11?

∴ The least number which leaves remainder 3 and 7 respectively when divided by 7 and 11 is 73.

What is the remainder of all integers between 2 and 6?

The answer is 301. You first must find a mechanism for finding a number that leaves a remainder of 1 when divided by all integers between 2 and 6. I’m assuming in this answer that your use of “between” is inclusive of 2 and 6.

What is the remainder of 2 divided by 3 and 4?

The answer is 11. When divided by 2 it gives 5, remainder 1; when divided by 3 it gives 3, remainder 2; and when divided by 4 it give 2, remainder 3. Note that the answer must be an odd number, since when divided by 2 it leaves a remainder of 1.

How do you find the multiples of the lowest one?

Subtracting 1 from such a number would give a number that leaves a remainder of 0 when divided by all integers between 2 and 6, or in other words, is divisible by all integers between 2 and 6. We can find the lowest such number, and then all other numbers that satisfy the requirements are multiples of the lowest one. The answer is 301.

Which number has a remainder of 25 when divided by 35?

Find the least number which when divided by 15, leaves a remainder of 5, when divided by 25, leaves a remainder of 15 and when divided by 35 leaves a remainder of 25. Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15.

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