Can the number 6n n being a natural number ends with the digit 0?

Solution: If any number ends with the digit 0 that means it should be divisible by 5. That is, if 6n ends with the digit 0, then the prime factorisation of 6n would contain the prime number 5. Therefore, 6n cannot end with the digit 0 for any natural number n.

Can 6n be a natural number?

R D Sharma – Mathematics 9 For any number ending with 5 the prime factor 5 should be there in its primefactorisation (for eg: 5=5,15=3×5,25=5×5). In all these 5 is a necessary prime number. But 6n has only 2 and 3 as prime factors.So 6n can never end with digit 5 for any natural number n.

Can the number 6n n being a natural number end with the number digit 5 give reasons?

No, because 6n = (2 × 3)n = 2n × 3n , so the only primes in the factorisation of 6n are 2 and 3, and not 5. Hence, it cannot end with the digit 5.

Why the number 16n where n is a natural number Cannot end with zero?

if any number ends with zero then it must has factors as 2,5 . Given,16=2*2*2*216=2^4here 5 is not hte facto of 16^n. hence,it can’t be end with digit zero..

For what value N 6n ends with zero?

If the number 6n ends with the digit zero (0), then it should be divisible by 5. We know any number with the unit place as 0 or 5 is divisible by 5. Therefore, the prime factorization of 6n doesn’t contain prime number 5. Thus it proves that 6n cannot end with the digit 0 for any natural number n.

Can 8n N being a natural number end with digit 0 give reason?

Answer: it is not possible because 0 is not a natural number it is a whole number…….

Can the number N being a natural number end with the digit 0 give reasons?

➡For a number to end with zero, it must have 10 i.e. 2 and 5 in its prime factorisation. ➡The prime factorisation of 4 does not include 5. ➡Hence, the number 4^n cannot end with the digit zero.

Can the number 12 N N being a natural number end with digit 5 give reasons?

Here, Number=12n where n stand for any natural number . Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.

Can the number 4n N being a natural number ends with the digit 0 give reasons?

R D Sharma – Mathematics 9 we know that any number ends with the digit 0 then whose factorisation is in the form of 2n*5n . but 4n doesnt contain the prime factor of 5 . hence 4n never ends with 0.

Why the number 8 n where n is a natural number Cannot end with 0?

For a number to end with the digit 0 it’s prime factorization should have 2 and 5 as a common factor. here 8^n = (2*4)^n doesn’t have 5 in its prime factorization. Therefore 8^n cannot end with the digit 0. Hope this helps!

Can we have any ne n where 7 ends with the digit zero?

its prime factorisation should have the factors of both 2 and 5 [ since 10=2×5 ]But we know that 7=7x1By the fundamental theorem of arithmetics we also know that there exist no other factors for 7. Thus we conclude that 7n cannot end with the digit 0 for any natural number n.

What is the last digit of 6n?

Answer : Given number is 6n, where n is the natural number ending with digit 5. So the number must be divisible by 5, if take first natural number ending with 5. So the last digit of 6n can never be 5.