For which integer n is 2 8 2 11 2 n is a perfect square?
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For which integer n is 2 8 2 11 2 n is a perfect square?
2^8 + 2^11 + 2^n is a perfect square if and only if n = 12.
For what value of n is a perfect square?
The only value of n is 1. The reason is given below. Among them at least any one of the square roots will be imperfect, therefore the whole equation becomes imperfect. So, n! is perfect only for n=1.
Is N 2 2 a perfect square?
There are no perfect squares between n2 and (n+1)2, exclusive. For n≥2, n2
Why is 2 a perfect square?
In mathematics, a square is a product of a whole number with itself. For instance, the product of a number 2 by itself is 4. In this case, 4 is termed as a perfect square….Example 1.
| Integer | Perfect square |
|---|---|
| 13 x 13 | 169 |
| 14 x 14 | 196 |
| 15 x 15 | 225 |
| 16 x 16 | 256 |
Is 11 a perfect square?
11 is a prime number and hence, it is not a perfect square.
What is the 11th square number?
121
“Is it possible to recreate this up to 12×12?”
| 0 Squared | = | 0 |
|---|---|---|
| 9 Squared | = | 81 |
| 10 Squared | = | 100 |
| 11 Squared | = | 121 |
| 12 Squared | = | 144 |
Is negative 64 a perfect square?
64 is a perfect square.
What is value of N in math?
In an equation, N represents a specific number, not any number. N + 9 = 12 means N is a number which, when added to 9, must give the answer 12. So N can only be the number 3 because only 3 + 9 is equal to 12.
Which is the least value of n for 2^8+2^11×2^n is a perfect square?
= (2^4)^2 [1+8×2^2]= (2^4)^2×33 = not a perfect square. Thus , n=0 is the least value of n for which 2^8+2^11×2^n is a perfect square. Answer.
What is the value of n for a perfect square?
Educators go through a rigorous application process, and every answer they submit is reviewed by our in-house editorial team. The value of n has to be determined such that 2^8+2^11+2^n is a perfect square. If this is a perfect square, 9 + 2^ (n-8) has to be a square.
Is 28 + 211 + 2n a perfect square?
By brute force, we may check that n = 12 is the smallest possible integer such that 28 + 211 + 2n is a perfect square. We also claim that this is the only integer.
What is the first integer value where 2n is greater than 1 000?
Nicely done! so it looks like n = 10 is the first integer value for n where 2 n is greater than 1, 000. The correct answer is A, 10. Simplifying the inequality was definitely very helpful.