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How do you find the area of a triangle with 3 vertices?

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How do you find the area of a triangle with 3 vertices?

To find the area of a triangle where you know the x and y coordinates of the three vertices, you’ll need to use the coordinate geometry formula: area = the absolute value of Ax(By – Cy) + Bx(Cy – Ay) + Cx(Ay – By) divided by 2.

What is the perimeter of a triangle with vertices 0 4 0 0 and 30?

Thus, the required perimeter of the triangle is 12 units.

What is the area of a triangle with vertices at 5 0 8 0?

6 sq units
The area of a triangle with vertices A(5, 0), B(8, 0) and C(8, 4) in square units is. =12|-20+32|=(12×12)=6 sq units.

What is the area of triangle when vertices are given?

The formula for the area of the triangle is given by S=12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)] , where, (x1,y1),(x2,y2),(x3,y3) are the coordinates of the three vertices of the triangle. The units of the area are assumed to be square units.

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How do you find area with 3 sides?

The area of an equilateral triangle can be calculated using the formula, Area = a2(√3/4), where ‘a’ is the side of the triangle. For example, if an equilateral triangle has a side of 6 units, its area will be calculated as follows. Area = a2(√3/4), Area = 62(√3/4) = 15.59 square units.

What is the perimeter of triangle with vertices 0 4?

Let the points are A (0, 4), O (0, 0) and B (3, 0). So, the correct answer is “12 units”.

What is the perimeter of triangle with vertices?

Perimeter= 3 + 5 + 4 = 12 To find the perimeter of the triangle, find the lengths of each side of the triangle using the distance formula. Use the distance formula to find the length between point A and B, B and C, C and A. Then add all three lengths together to get the perimeter.

What is triangular area?

The area of each triangle is one-half the area of the rectangle. So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

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What is the formula of Triangle in coordinate geometry?

The formula of area of triangle formula in coordinate geometry the area of triangle in coordinate geometry is: A = (1/2) |x1 1 (y2 2 − y3 3 ) + x2 2 (y3 3 − y1 1 ) + x3 3 (y1 1 − y2 2 )|, where (x1 1 ,y1 1 ),(x2 2 ,y2 2 ), and (x3 3 ,y3 3 ) are the coordinates of vertices of triangle.

What is the area of a triangle with vertices at (- 2 1?

The area of a triangle with vertices at (-2, 1), (2, 1), and (3, 4) is 6 sq. units.

How to find area of triangle if we only know vertices?

But, how can we find area of triangle if we know only the coordinates of vertices of triangle. If, we know the vertices of triangle then we can definitely use distance formula to find the length of all the sides which can enable us to use Heron’s formula to find area of triangle. But, this will become too much lengthy and tedious.

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What is the altitude of the rightmost vertex of a triangle?

Area of a triangle is 1 2 b h, where h is some altitude of the triangle and b is a side perpendicular to h. So if we choose the side with vertices ( 0, 0) and ( 0, 3) as b, then clearly the altitude has lenghth 4, since this is the distance of the rightmost vertex.

How do you find the area of a triangle using determinants?

Solution: Using determinants we can easily find out the area of the triangle obtained by joining these points using the formula \\alpha = \\frac 12\\left| \\begin {matrix} x_1 & y_1 & 1\\cr x_2 & y_2 & 1 \\cr x_3 & y_3 & 1 \\cr \\end {matrix} \\right| .

What are the coordinates of the vertices of a trapezium?

Let the coordinates of vertices are (x1, y1), (x2, y2) and (x3, y3). We draw perpendiculars AP, BQ and CR to x-axis. = Area of Trapezium ABQP + Area of Trapezium BCRQ – Area of Trapezium ACRP