How do you find the max 3 elements in an array?

a) Let current array element be x. b) If (x > first) { // This order of assignment is important third = second second = first first = x } c) Else if (x > second) { third = second second = x } d) Else if (x > third) { third = x } 3) Print first, second and third. Below is the implementation of the above algorithm.

How do you find the maximum number of 4 numbers?

Algorithm

1. START.
2. INPUT FOUR NUMBERS A, B, C, D.
3. IF A > B THEN. IF A > C THEN. IF A > D THEN. A IS THE GREATEST. ELSE. D IS THE GREATEST.
4. ELSE IF B > C THEN. IF B > D THEN. B IS THE GREATEST. ELSE. D IS THE GREATEST.
5. ELSE IF C > D THEN. C IS THE GREATEST.
6. ELSE. D IS THE GREATEST.

How many comparisons do we need to find the largest and the smallest of 2N integers?

It needs at least N-1 comparisons if the largest 2 elements are at the beginning of the array and at most 2N-3 in the worst case (one of the first 2 elements is the smallest in the array).

How do I find the second largest number in C++?

The program output is shown below.

1. #include
2. using namespace std;
3. int main ()
4. {
5. int A[10], n, i, j, x;
6. cout << “Enter size of array : “;
7. cin >> n;
8. cout << “Enter elements of array : “;

How do you find the third maximum number?

Find 3rd Largest Number in Array using Collections

1. import java.util.*;
2. public class ThirdLargestInArrayExample2{
3. public static int getThirdLargest(Integer[] a, int total){
4. List list=Arrays.asList(a);
5. Collections.sort(list);
6. int element=list.get(total-3);
7. return element;
8. }

How do you find the third largest element in a list Python?

Find the third largest number in a list in python

1. +1. l=[5,8,2,9,4,10,7] print(“3rd largest in”,l,”is”,sorted(l)[-3]) 28th May 2018, 3:28 AM.
2. +13. Convert the list into a set.
3. +9. 2nd variant without using sort(): https://code.sololearn.com/cxKFjv7q5PQ8/#py.
4. +8. #If you are not allowed to use sort, try this.

How do you find the largest of 4 numbers in C?

Welcome to the world of programming.

How many comparisons are necessary to find the largest and smallest of a set of n distinct elements?

Lower bounds for the MIN and MAX Claim: Every comparison-based algorithm for finding both the minimum and the maximum of n elements requires at least (3n/2)-2 comparisons.

What is the minimum number of comparisons to find the 2nd largest element provided you have found the largest element?

In short, the Minimum Comparisons to find Second Largest Element or Second Smallest Element is N + logN – 2 comparisons . Hence, if there are 1024 elements, then we need at least 1024 + 10 – 2 = 1032 comparisons.

How do you find the third largest number in an array in C++?

First, iterate through the array and find maximum. Store this as first maximum along with its index. Now traverse the whole array finding the second max, excluding the maximum element. Finally traverse the array the third time and find the third largest element i.e., excluding the maximum and second maximum.

How do you find the largest number in a list C++?

To find the largest element, the first two elements of array are checked and largest of these two element is placed in arr[0] . Then, the first and third elements are checked and largest of these two element is placed in arr[0] . This process continues until and first and last elements are checked.