Common questions

How do you find the perimeter of a isosceles triangle if the area is given?

How do you find the perimeter of a isosceles triangle if the area is given?

The formula to calculate the perimeter of an isosceles triangle is P = 2a + b where ‘a’ is the length of the two equal sides and ‘b’ is the base of the triangle.

How do you solve a isosceles triangle?

Write the formula 2a + b = 180 on a piece of paper. The letter “a” stands for the two congruent angles on the isosceles triangle, and the letter “b” stands for the third angle. Insert the known measurements into the formula. For instance, if angle “b” measures 90, then the formula would read: 2a + 90 = 180.

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How do you find height of an isosceles triangle?

We can find the height by splitting the isosceles triangle into two right-angled triangles and then applying Pythagoras’ Theorem to one of them. h = 13.20 ( t o 2 d . p . ) We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.

What is the height formula of isosceles triangle?

Also,

The perimeter of the isosceles triangle P = 2a + b
The altitude of the isosceles triangle h = √(a2 − b2/4)

What is the value of the base of an isosceles triangle?

Originally Answered: The area of an isosceles triangle is 12cm. If one of its equal sides is 5cm, what is the value of its base? Area of isosceles triangle = 12 sq cm. The equal sides are 5 cm.

What is the base of the triangle whose area is 12cm?

The basic Pythagoran triangle is 3 cm–4 cm–5 cm. So the base of each of the two right angled triangles could be either 3 cm or 4 cm and the corresponding height 4 cm or 3 cm, respectively. Therefore the base of the original triangle whose area = 12 sq cm can be 6 cm or 8 cm.

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How to find the perimeter of an isosceles right triangle?

The perimeter of an isosceles right triangle is the sum of all the sides of an isosceles right triangle. Suppose the two equal sides are a. Using Pythagoras theorem the unequal side is found to be a√2. Question 1: Find the area of an isosceles triangle given b = 12 cm and h = 17 cm?

How do you find the area of a 5-5-8 triangle?

Check the area by Heron’s formula, both a 5–5–8 and a 5–5–6 triangle have an area of 12 cm² The area of an isosceles triangle is 60 cm sq, and the length of each one of its equal side is 13 cm.