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How do you find the point on a line closest to the origin?

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How do you find the point on a line closest to the origin?

  1. (Using y-intercept form for the equation of a line, where m = slope and b is the y-intercept, we have:
  2. y = mx + b.
  3. The point on the line closest to the origin will always be the point at which a line perpendicular to the line in question passes through the origin.
  4. M = (-1/m)

Which point is on the line y =- 3x 4?

1 Expert Answer y=3x-4 is the slope-intercept form of the equation of a line. It is in the form y=mx+b. m is the slope (often called “rise over run”) and b is the y-intercept (the point where x=0). The y-intercept is the point (0,-4).

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What is the point on the line y 3x 5 that is closest to the origin?

Summary: The point on the line y = 3x + 5 that is closest to the origin is (-3/2, 1/2).

Which point is on the line y 2x 3?

Closest point from origin will be the perpendicular distance from origin to the line. We need to find an equation of the perpendicular from (0,0) on y = 2x + 3. Therefore, the point on the line is (-6/5, 3/5).

Which point is not on the line y 3x 4?

4,12 is the correct ans.

What is the slope of the line y 3x 4?

Algebra Examples Using the slope-intercept form, the slope is −3 .

At which points on the curve Y 1 40×3 − 3×5 does the tangent line have the largest slope?

At which points on the curve y =1+40×3 – 3×5 does the tangent line have the largest slope? The points which maximizes the tangent line slope are therefore (2, 225) and (-2, -223).

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What point on the line y 2x 5 is closest to the origin?

(2.1) is the closest point, √22+1=√5 from the origin.

What is the closest point to the origin on the line?

Now, let distance of point ‘P’ from the origin be ‘s’. Since ‘P’ is the closest point to the origin, its distance from the origin must be minimum. Hence, the closest point to the origin on the given line is (1.2 , 7.6).

What is the point of intersection between y = 3x + 4?

And it comes out to be the point of intersection between the line y = 3x + 4 with x + 3y = 0, solve the both and you will get the answer easily. Suppose P (a,b) be the point on the line y = 3x+4 closest to the origin. Thus, P is (a,3a+4). Now, let distance of point ‘P’ from the origin be ‘s’.

What is the distance from line 3x – 4Y + 15 =0?

We of course reject -3 since the distance can’t be negative, concluding that the distance from line 3x – 4y + 15 =0 to the origin is 3. We now know that distance from the origin to the line via the x-axis is 5. We now need to find the angle between line 3x – 4y + 15 =0 and the x-axis. We can find it using the gradient.

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What is the minimum distance from the origin of the line?

Since ‘P’ is the closest point to the origin, its distance from the origin must be minimum. Hence, the closest point to the origin on the given line is (1.2 , 7.6). We know that the minimum distance between a point and a straight line is the perpendicular drawn from the given point on the given line.