How do you find the smallest positive integer n?

Explanation: Find when √x−√x−1=0.01 . Then, n would be the smallest positive integer greater than x . (√x−√x−1)⋅(√x+√x−1)=0.01(√x+√x−1) , or 1=0.01(√x+√x−1) .

What is the smallest number that has exactly 7 factors?

64 is the smallest. It has these 7 factors: 1,2,4,8,16,32, and 64. 12 has 6 factors (1,2,3,4,6 and 12) and 24 has 8 factors (1,2,3,4,6,8,12 and 24) but you have to go all the way to 64 to get exactly 7 factors.

What is the smallest positive integer that is non prime and is not a factor of 9 factorial?

The smallest positive integer which is non prime and not a factor of 9 is 4. Since 1 is neither prime nor composite number but it is a factor of 9. Remaining 2 and 3 are prime numbers. Hence 4 is the least non prime not a factor of 9 positive integer.

What is the smallest positive integer that has exactly 7 positive?

So, the smallest number that will have 7 factors, N = 26 = 64.

What is the smallest positive integer n for which 1 i1 − i n 1?

The smallest positive integer n for which ((1+i)/(1-i))^n = 1 is, (1) n = 8, (2) n = 16, (3) n = 12, (4) none of these. Here the smallest number of n is 4. Hence option (4) is the answer.

What is the smallest positive integer n for which 1 i 2n 1 − I 2n?

2
Here the smallest number of n is 2.

What is the smallest positive integer that has exactly 12 positive?

This means that 60, 72, and 84 should be the smallest three numbers with 12 factors.

What is the smallest positive integer with exactly 16 positive factors?

The smallest positive integer with 16 divisors is 120.

What are least positive integers?

So, the number 1 is the smallest positive integer.

What is the smallest positive integer that is not prime and not a factor of eleven factorial 11 !)?

implementing this rule, we just need to take 11 and multiple it with the first number bigger then 1 (to make the number not prime) => 2X11 = 22.

What is the smallest positive integer with exactly 6 factors?

What is the smallest positive integer with 6 divisors? Taken precisely as stated, the answer is clearly 1. 1×1×1×1×1×1=1. If you want six unique divisors, the answer is still 1.

What is the smallest positive integer n for which 1 i1 − i n 1 if there is no such integer answer none?

4
The smallest positive integer n for which ((1+i)/(1-i))^n = 1 is, (1) n = 8, (2) n = 16, (3) n = 12, (4) none of these. Here the smallest number of n is 4. Hence option (4) is the answer.

How to find the smallest number evenly divisible by first n numbers?

Smallest number divisible by first n numbers. Given a number n find the smallest number evenly divisible by each number 1 to n. Examples: If you observe carefully the ans must be the LCM of the numbers 1 to n. Initialize ans = 1. Iterate over all the numbers from i = 1 to i = n. At the i’th iteration ans = LCM(1, 2, …….., i).

How to find the smallest prime divisor of a given number?

Approach: 1 Check if the number is divisible by 2 or not. 2 Iterate from i = 3 to sqrt (N) and making a jump of 2. 3 If any of the numbers divide N then it is the smallest prime divisor. 4 If none of them divide, then N is the answer.

What are the two cases in which the output is N+10?

For a given n, following are the two cases to be considered. Case 1: n < 10 When n is smaller than 10, the output is always n+10. For example for n = 7, the output is 17.

How to find the LCM of the numbers 1 to N?

If you observe carefully the ans must be the LCM of the numbers 1 to n . Initialize ans = 1. Iterate over all the numbers from i = 1 to i = n. At the i’th iteration ans = LCM (1, 2, …….., i). This can be done easily as LCM (1, 2, …., i) = LCM (ans, i) . Note : In C++ code, the answer quickly exceeds the integer limit, even the long long limit.