How do you find the sum of a GP with infinite terms?

The nth term from the end of the GP with the last term l and common ratio r = l/ [r (n – 1)]. The sum of infinite, i.e. the sum of a GP with infinite terms is S∞= a/ (1 – r) such that 0 < r < 1. If three quantities are in GP, then the middle one is called the geometric mean of the other two terms.

What is the formula for the general form of a GP?

Geometric Progression Formulas The general form of terms of a GP is a, ar, ar2, ar3, and so on. Here, a is the first term and r is the common ratio. The nth term of a GP is Tn = arn-1 Common ratio = r = Tn/ Tn-1 The formula to calculate the sum of the first n terms of a GP is given by: Sn = a [

How do you find the sum of the first n terms?

The formula to calculate the sum of the first n terms of a GP is given by: . Sn = a[(rn-1)/(r-1)] if r ≠ 1and r > 1. Sn = a[(1 – rn)/(1 – r)] if r ≠ 1 and r < 1. The nth term from the end of the GP with the last term l and common ratio r = l/ [r(n – 1)].

What is the geometric mean of a finite GP with n terms?

If three quantities are in GP, then the middle one is called the geometric mean of the other two terms. If a, b and c are three quantities in GP, then and b is the geometric mean of a and c. This can be written as b2 = ac or b =√ac Suppose a and r be the first term and common ratio respectively of a finite GP with n terms.

How do you find the remainder of a series?

We use a series 1, 3, 2, -1, -3, -2 to find the remainder (Intuition behind the series is discussed below). Initialize the result as 0. Traverse num from end and above series from beginning. For every traversed digit, multiply it with next digit of series, and add the multiplication to result.

How do you find the remainder of 24 divided by 7?

How do I calculate the remainder of 24 divided by 7? Subtract 7 from 24 repeatedly until the result is less than 7. 24 minus 3 times 7 is 3. The number that is left, 3, is the remainder.