How do you solve for domain and range?

To find the domain and range, we simply solve the equation y = f(x) to determine the values of the independent variable x and obtain the domain. To calculate the range of the function, we simply express x as x=g(y) and then find the domain of g(y).

How do you find the solution in math?

A solution is any value of a variable that makes the specified equation true. A solution set is the set of all variables that makes the equation true. The solution set of 2y + 6 = 14 is {4}, because 2(4) + 6 = 14. The solution set of y2 + 6 = 5y is {2, 3} because 22 + 6 = 5(2) and 32 + 6 = 5(3).

What is the value of 4×2 + 6x + 21?

4x² + 6x + 21=0 where 4x²+6x+21 is considered as a polynomial expression which is written on the left side and has been fixed to make the polynomial expression equal to zero to form a complete polynomial equation.

How to solve 2x-7/4 =X+3/3?

Add 1 2 and 2 1 to get 3 3. Divide both sides by 2. Divide both sides by 2. 2x-7/4=x+3/3 One solution was found : x = 11/4 = 2.750 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

How to multiply 4x by x + 3 using distributive property?

Use the distributive property to multiply 4 by x+3. Use the distributive property to multiply 4 by x + 3. Subtract 4x from both sides. Subtract 4 x from both sides. Combine 6x and -4x to get 2x. Combine 6 x and − 4 x to get 2 x. Add 21 to both sides. Add 2 1 to both sides. Add 12 and 21 to get 33. Add 1 2 and 2 1 to get 3 3. Divide both sides by 2.

Is x2 – 2x – 2 factorable over the reals?

We could say that x2 − 2x − 2 is not factorable over the rational numbers. That is it has no factors whose coefficients are rational numbers. However it is factorable if you allow irrational coefficients. The next level would be Complex coefficients. For example: The quadratic x2 − 2x + 2 is not factorable over the reals.