How fast must the Earth rotate to neutralize gravity?

We can calculate how fast the Earth would need to spin to balance the force of gravity (this is known as the ‘escape velocity’). It works out at about 28,437km/h (17,670mph). The Earth would have to spin once every 84 minutes to achieve that speed at the equator, or about 17 times faster than it actually spins.

What is the 9.8 m s2?

The magnitude of the acceleration due to gravity, denoted with a lower case g, is 9.8 m/s2. g = 9.8 m/s2. This means that every second an object is in free fall, gravity will cause the velocity of the object to increase 9.8 m/s. So, after one second, the object is traveling at 9.8 m/s.

How long would a day last if Earth were rotating so fast that the acceleration of an object on the equator were equal to G?

Eight meters per second squared. And so the period here would be would be equal to 5070 seconds approximately. Or we can say approximately 1.4 hours.

Does the Earth’s spin affect gravity?

While the spinning of the Earth doesn’t directly affect gravity, it does off-set it a little. At the north and south poles objects weigh exactly what they should, and at the equator things weigh slightly less.

How long will it take to fall?

Gravity accelerates you at 9.8 meters per second per second. After one second, you’re falling 9.8 m/s. After two seconds, you’re falling 19.6 m/s, and so on.

Is gravity 9.8 meters per second?

At Earth’s surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second. Thus, for every second an object is in free fall, its speed increases by about 9.8 metres per second. At the surface of the Moon the acceleration of a freely falling body is about 1.6 metres per second per second.

How long would a day be if the Earth were rotating so fast?

With a 1 mph speed increase, the day would only get about a minute and a half shorter and our internal body clocks, which stick to a pretty strict 24-hour schedule, probably wouldn’t notice. But if we were rotating 100 mph faster than usual, a day would be about 22 hours long.

How many hours would make a day of the Earth is rotating?

Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes and 4 seconds with respect to other distant stars (see below). Earth’s rotation is slowing slightly with time; thus, a day was shorter in the past.

Does the Earth spin fast or slow?

Earth spins on its axis once in every 24-hour day. At Earth’s equator, the speed of Earth’s spin is about 1,000 miles per hour (1,600 km per hour).

What happens if the Earth spins faster?

The faster the Earth spins, the shorter our days would become. With a 1 mph speed increase, the day would only get about a minute and a half shorter and our internal body clocks, which stick to a pretty strict 24-hour schedule, probably wouldn’t notice.

How fast does the Earth spin?

This means that, in order to feel pretty much weightless (while standing on the surface of earth at sea level, on the equator), the earth would have to spin approximately 17 times faster, and one full day (sunrise to sundown to next sunrise) would last 84 minutes.

What would happen if your weight was zero at the equator?

It is a constant, like g, so we can put them together) If your weight, at the equator, would be zero when the Earth spins at 7,906 m/s, any number bigger than that would result in negative weight and cause you to float off of the surface. For context, the International Space Station orbits the Earth at about 7,660 m/s.

How do you find the centripetal acceleration of an object weightless?

The centripetal acceleration is, a=r x (w^2), here r is radius of earth and w is angular velocity. We can calculate w as we know the value of a and r. W=0.00124 rad/s. So,this must be speed of earth to make an object weightless. Now, w=2/T. Putting value of w, we get T which is 5075 sec or say 1.41 hours (To rotate around its axis)

How long does the Earth’s rotation period take?

All in all, that means the rigid-Earth value of a 1.41 hour rotation period is an upper bound; the actual rotation period of a non-rigid Earth allowed to come to equilibrium with net zero gravity at the equator in its co-rotating frame would be somewhat longer than that.