How many 2 digit numbers are there divisible by 4?
Table of Contents
- 1 How many 2 digit numbers are there divisible by 4?
- 2 How many 2 digit numbers are there that are divisible by 5?
- 3 How many two digit numbers are there which are divisible by 8?
- 4 How many 3-digit numbers end in 3 and are divisible by 3?
- 5 How many 6-digit numbers can be formed from 2/3 2 0/3 3?
- 6 What is the lowest 3 digit number that is divisible by 15?
How many 2 digit numbers are there divisible by 4?
22 two-digit numbers
So, the series of 2-digit numbers which are divisible by 4 consists of a total 22 terms. Therefore, there are a total 22 two-digit numbers which are divisible by 4.
How many 2 digit numbers are there that are divisible by 5?
18 two-digit numbers
Hence 18 two-digit numbers are divisible by 5.
What is the sum of all two digit numbers divisible by 3?
∴ the sum of all two digit positive numbers divisible by 3 is 1665.
How many 2 digit numbers are there which are divisible by 6?
15
So the number of two digit numbers which are divisible by 6 are 15.
How many two digit numbers are there which are divisible by 8?
96. So there are total 11 two digit numbers which are divisible by 8.
How many 3-digit numbers end in 3 and are divisible by 3?
300 3-digit numbers divisible by 3.
How many two digit numbers are divisible by 3?
How many two digit numbers are divisible by 3? An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant. A.P = 12,15,18,…,99 ∴ Two digit numbers divisible by 3 = 30.
How many multiples of 5 are evenly divisible by 3?
Since we know this universe is made up of 180 multiples of 5, the answer to how many multiples of 5 in the universe of 3 digit numbers are also evenly divisible by 3 would me 180 opportunities times 1/3. There are 66 numbers divisible by 3 and 5, starting from 15, 30, 45, etc. They are 105, 120, 135, 150, 165, 180, 195 etc.
How many 6-digit numbers can be formed from 2/3 2 0/3 3?
There are 5!/ (2!*3!) = 120/12 = 10 such arrangements of 0 in front of the 5 nonzero digits. Therefore, there are 60 -10 = 50 valid 6-digit numbers that can be formed from 2 3 2 0 3 3. The smallest number is 202333, and the largest 333220.
What is the lowest 3 digit number that is divisible by 15?
In order for a number to be divisible by 3 and 5, it muddy be divisible by 15 (3*5, this rule can be generalized for any numbers). The lowest 3 digit number divisible by 15 is 105 (or 15*7). The highest number that is divisible by 15 and still 3 digits is 990 (which is 15*66).