How many grams of H2O will be produced if you start with 32 g of O2?

32g O2 x 36.03056g H20/31.9988g O2 this way the O2 cancels out and you are left with just the H2O so your raw answer would be 36.0319112, then if your instructor requires a significant figure answer that would be to 2 significant figures the information you were given 32g O2, so as above 36g or Water are produced.

How many grams of H2O are produced if 2.02 g of H2 react with excess O2?

The answer is 18 grams.

What amount of H2O will be produced by 1g of hydrogen?

We are given: The 1g of hydrogen combines completely with 8g of oxygen to form water that means the ratio is 1:8.

How many grams of water should you produce?

This reaction clearly tells that 2 moles of hydrogen and 1 mole of oxygen produce 2 moles of water. The molar mass of hydrogen is 2, oxygen is 32 and water is 18. Hence, with 8 grams of both hydrogen and oxygen, the mass of water produced is 9 gram.

How many grams of water are produced by the complete combustion of methane?

Mass of water produced by complete combustion of 12 gram of methane gas is 27 grams.

How many moles of O2 are produced from 6.2 moles of water?

Then we get 6.2 moles of H2 and we get 3.1 moles of O2.

How many moles of water can be produced if 4 moles h₂ are used?

This leaves you with 8 moles of hydrogen left over. 2H2 +O2 ======> 2H2O. 2- moles of hydrogen reacts with 1- mole of oxygen to give 2- moles of water. So 4- moles of Oxygen will react with 8- moles of Hydrogen to form 4- moles of water.

How many grams of H2O will be formed when 16.0 g H2 is allowed to react with 16.0 g O2 according to?

2 g (1 mole) of H2 combines with 16 g (half mole) of O2 to form 18 g (one mole) of H2O.

How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen?

10.7 grams
Therefore, 10.7 grams of Hydrogen are necessary to fully react with 50.0 grams of Nitrogen.