How many green and red balls are there in each bag?

A bag A contains 4 green and 6 red balls. Another bag B contains 3 green and 4 red balls. If one ball is drawn from each bag, find the probability that both are green.

What is the probability of drawing a green white and non-red ball?

The probability of drawing a ball that is simultaneously “green, white and non-red” is zero, as there are no balls that are both green and white. Three balls are drawn one after the other from a bag containing 6 red balls, 5 yellow balls and 3 green balls.

What is the probability that a box contains 4 blue balls?

Two green balls out of five can be chosen in (5C2) = 10 ways. Four balls out of nine can be chosen in (9C4) = 126 ways. Therefore, the probability = [ (6*10) / 126] = (10 / 21). Originally Answered: A box contains 4 blue and 5 green balls.

How many blue and green balls are in a 4-ball box?

= 6/11. There is an odd of 6 to 5 of getting a 4-ball combination where there are two blue balls and two green ball. Please keep asking questions and leave an upvote. Originally Answered: A box contains 4 blue and 5 green balls. Four balls are drawn randomly and replaced.

A bag A contains 4 green and 6 red balls, Another bag B contains 3 green and 4 red balls. If one ball is drawn from each bag, find the probability that both are green.

What is the probability of getting green and red balls?

Lets say we get red ball from bag 2 and green from bag 1. Then the probability of that being true is 3/8×4/10=3/20. Lets say bag1 has 5 red balls and 3 green balls while bag 2 has 4 red balls and 6 green balls.

How many ways are there in 9 balls in the bag?

The bag contains 2 White, 3 Black and 4 Red balls. So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls. Three balls can randomly be drawn in (9C3) = 84 ways. 1 Black and 2 non-Black balls can be drawn in (3C1)* (6C2) = 45 ways.

How many balls are there in the bag of cards?

One ball is drawn from the first bag and placed unseen in second ba Question 892094: One bag contains 4 white balls and 3 black balls and a second bag contains 3 white balls and 5 black balls. One ball is drawn from the first bag and placed unseen in second bag.

How many red and white balls are there in a box?

A box contains 5 different red and 6 different white balls. In how many ways can 6 balls be selected so that there are at least two balls of each color? A box contains 5 different red and 6 different white balls. In how many ways can 6 balls be selected so that there are at least two balls of each color? Was this answer helpful?

What is the probability of the second ball being yellow?

We will consider both problems. The ball is not put back before drawing next ball. The probability of the first ball being yellow is 5/ (4+5+6) = 5/15. Under this condition the probability of the second ball being yellow is 4/ (4+4+6)=4/14. Under this condition probability of the third ball being yellow is 3/ (4+3+6)=3/13.

What is the required probability of 2 balls from a jar?

Thus, the required probability = (120 / 455) = (24 / 91) ≈ 0.2637. A jar contains 6 red balls, 3 green balls, 5 white balls, and 7 yellow balls. Two balls are chosen from the jar, with replacement.

How many green balls are in a jar of balls?

A jar contains 6 red balls, 3 green balls, 5 white balls, and 7 yellow balls. Two balls are chosen from the jar, with replacement. What is the probability that both balls chosen are green? We’ll call the balls by the initial letter of their collors to make it easier. In total, there are 6R + 3G + 5W +7Y = 21balls.

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