How many numbers between 3000 and 8000 can be formed by using the digits 2 4 6 and 8 if all digits are allowed to be repeated?

Thus, there are 60 numbers lying between 3000 and 4000 that can be formed using the digits 3, 4, 5, 6, 7, and 8, where no digit is repeated.

How many numbers between 2000 and 3000 can be formed with the digits 0?

Answer: 210 numbers can be formed between 2000 and 3000.

How many digits between 5000 and 7000 can be formed using the digits 3 to 8?

The Numbers between 5000 and 7000 can be formed using the digits 3 to 8, when any digit can occur any number of times is 432.

How many numbers between 2000 and 5000 can be formed with the digits?

We can have 120 such numbers.

How many numbers divisible by 5 and lying between 3000 and 4000 can be formed from the digits 123456?

The numbers lying between 3000 and 4000 which are divisible by 5 and has 3 on hundredth’s place and 5 on one’s place and the total number of digits is 4. Hence, total 12 number can be formed.

How many numbers between 20 and 5000 are formed?

The same logic applies – the first digit can only be 2 , 3 , or 4 , and there are 6 numbers that can be formed for each of these. That makes a total of 6×3=18 numbers with this set. So, the final answer is 12+18=30 numbers.

How many numbers between 200 and 2000 can be formed with the digits 1 2 3 4 where repetition of digits are allowed repetition of digits is not allowed?

The answer is 3,240. The answer is 3,240.

How many times does the digit 5 occur between 5000 to 6000?

If the number are in 5000-6000 so the number must be form 4 digit and first digit became 5. =60. There’s only one choice for the first digit and five for the second, four for the third and three for the last digit. In total, 60 if no digits are repeated.

How many numbers divisible by 5 and lying between 3000 and 4000 can be formed?

12 numbers
So, 12 numbers are there between 3000 and 4000 divisible by 5 without repeating the digits.

How many numbers are divisible by 5 and lying between 4000 and 5000?

There are 25 numbers which are divisible by 5 and lying between 4000 and 5000 and can be formed from the digits 4, 5, 6, 7, 8 with repetition of digits.

How many numbers are 1 digit occupied between 3000 and 5000?

The answer is 240. Because you specified between 3000 and 5000, the first digit must either be a 3, or a 4. That’s 2 choices. 1 digit occupied. We are left with 6 more numbers.

How many possible combinations can be made with 7000 repeats?

Overall, using this you can make 3 ∗ 8 ∗ 7 ∗ 6 = 1008 such numbers. The first digit can be 4,5,6 footie that we exclude 7 because 7000 repeats 0, so there are 3 possible choices for the first digit. Then you have 8 choices (0,1,2,3,4,5,6,7,8 excluding the first digit) for the next digit, and each following digit has one less.

How many possible numbers are there in 1×5×4×3?

4th and last digit can be any of the three remaining digits. 1×5×4×3 = 60 possible numbers. This is two questions, one answer with repeats and one answer without. Let’s do the “Without” case first. BETWEEN 5000 AND 6000 WITHOUT REPEATS. 1st digit must be 5.

How many numbers between 2000 and 5000 are divisible by 3?

Total number of numbers between 2000 and 5000 divisible by 3 are 12+12+6 = 30. Option A is correct. Was this answer helpful?