# How many numbers can be formed from 5 digits?

Table of Contents

- 1 How many numbers can be formed from 5 digits?
- 2 How many 5 digit odd numbers can be formed from the digits 012345?
- 3 What is the the probability of getting a sum divisible by five if a pair of fair dice is rolled?
- 4 What is the probability that all two numbers are divisible by 4?
- 5 How many ways can a 5-digit number be formed with 3 digits?

## How many numbers can be formed from 5 digits?

So, the number of 5-digit numbers that have zero as the first digit are 10 × 10 × 10 × 10 = 10,000. If we subtract these 10,000 ways from the overall 1,00,000 ways, we are left with 90,000. Therefore, there are 90,000 unique 5-digit numbers possible.

## How many 5 digit odd numbers can be formed from the digits 012345?

=72 odd numbers possible.

**What is the probability of getting a number divisible by 5?**

There is a 22\% chance that with two dice you will roll a number that can be divisible by five.

### What is the the probability of getting a sum divisible by five if a pair of fair dice is rolled?

Each dice has six combinations which are independent. Therefore the number of possible outcomes will be 6*6 = 36. The probability of rolling a pair of dice whose numbers add to 5 is 4/36 = 1/9.

### What is the probability that all two numbers are divisible by 4?

The event that the two digit numbers formed by the digits 1, 2, 3, 4, 5 are divisible by 4 = {12, 24, 32, 44, 52} Hence, the required probability = 5/25 = 1/5. Was this answer helpful? Thank you.

**How many 5 digit numbers are divisible by 4?**

∴ Total number of 5–digit numbers that can be formed using the digits 0, 1, 2, 3, 4 = 5! – 4! = 120 – 24 = 96. Now, only these numbers are divisible by 4 in which the numbers formed by the last two digits is divisible by 4. Thus, the numbers ending in 04, 12, 20, 24, 32 and 40 will be divisible by 4.

## How many ways can a 5-digit number be formed with 3 digits?

The numbers formed by using these digits should have the last two digits as 12 or 24 or 32 or 20 or 04 or 40 so that they are divisible by 4. Hence the number divisible by 4 in the above case can be formed in 3! × 3 = 18 ways. In each case, the five-digit number can be formed using the remaining 3 digits, but ‘0’ cannot exist in the first place.