How many numbers greater than 3000 can be formed from digits 1 2 3 4 and 5 using each digit no more than once in each number?

The answer is 72. There are three choices for the first number, and 4 choices for the last number, *except* for the ones that used 7 for the first. The first number must be 6,7 or 8, and the last number must be 1, 3, 5, or 7.

How many 5 digit numbers can be formed from the digits 1 2 3 4 5 using the digits without repetition how many are even and greater than 30000?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.

How many different four-digit numbers are there where all the digits in each number are different?

Hence by the fundamental counting principle, The number of 4-digit numbers are 9.9. 8.7 = 4536. Therefore, there are 4536 four-digit numbers with distinct digits.

How many 3 digit numbers can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits are repeated?

There is 5 possible ways to fill ten’s place. There is 4 possible ways to fill hundredth place as digits cannot be repeated. ∴ 3 – digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 is 20.

How many numbers greater than 2000 can be formed with 12345?

The answer is 72. We can make either four or five-digit numbers that satisfy the criteria.

How many numbers greater than 1000 can be formed?

Therefore, 60 numbers greater than 1000 are possible.

How many 3 digit numbers can be formed from 400 numbers?

Hence there are 100 3 digit number that can be formed from the digits 3, 4, 5, 7, 8 and 9 such that the number formed is greater than 400 and no digit in the number is repeated.

How many permutations of five-digit numbers are greater than 3000?

All five-digit numbers are greater than 3000, and there are 5! = 120 permutations of the five digits. Four-digit numbers greater than 3000 must have one of three digits (3 or 4 or 5) as its first digit. The next three digits must be selected from the four remaining digits available, so the number of permutations is: 4 * 3 * 2 = 24.

How many five digit numbers are larger than 3000?

All of the five digit numbers are larger than 3,000 so any combination works. This means we do 5! (5•4•3•2•1) which equals 120 five digit numbers. That means in total we have 72+120=192 numbers larger than 3,000. We can make either four or five-digit numbers that satisfy the criteria.

How many numbers can you start with a 3 and 4?

If you start with a 4, you have three choices for each other space, except you can’t have 222 or 333, so there are 25. If you start with a 3 it is harder as you have a different number of each digit left, but it is the same idea.