How many times does the digit 2 occur between 1 and 1000?

Digit 2 appears 20 times in first 100 natural numbers.

How many 4 digit passwords formed from numbers 0 to 9 if repetition of digits is not allowed?

Originally Answered: How many 4-digit combinations are possible using 0-9 without repeating any numbers? 5,040. If we were choosing any 4-digit number, we would have 10 choices for the first, 10 for the second, 10 for the third, and 10 for the fourth.

How many times the digit 3 appears in numbers from 1 to 1000?

Each of these numbers has two 3, that is at the ten’s and unit’s place. Therefore, the number of times 3 appears in these 8 numbers is 16. The four digit number 1000 has no digit 3. Therefore, the number of times 3 comes in 1 to 1000 is the sum of the number of times 3 comes in 1 to 9, 10 to 99, and 100 to 999.

How many 4 digit numbers can be formed by using the digits 3 4 9 and 0 without repeating any digit?

120 combinations can be formed.

How many 4 digit numbers can be formed using the digits 4 3 0 9 without repeating the digits?

How many times does the digit 3 appear from 1 to 10,000?

The digit “3” occurs 3980 times in all numbers from 100 to 10,000.

How many ways can a 5-digit number be filled up?

A five-digit number cannot have 0 as the first digit on the left, which is the ten thousand place. Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways.

Can the digit at the ten thousand place in a number?

The digit at the ten thousand place in a 5-digit number can never be 0. Example 1: Find the sum and difference of the greatest 5-digit number and the smallest 5-digit number. The greatest 5-digit number is 99,999. The smallest 5-digit number is 10,000.

How do you write 20340 as a five-digit number?

Let us continue with the same number 20340. 2 is in Ten Thousands place = 2 × 10000 = 20000. 0 is in Thousands place = 0 × 1000 = 0. 3 is in Hundreds place = 3 × 100 = 300. 4 is in Tens place = 4 × 10 = 40. 0 is in Units place = 0 × 1 = 0. Hence, the five-digit number can be expressed in the following way: 20000 + 0 + 300 + 40 + 0 = 20340 .

What is the total number of combinations possible with 5 numbers?

Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways. Therefore, the total number of combinations possible are 10 × 10 × 10 × 10 × 10 = 1,00,000.