How many ways are there to arrange 5 boys and 5 girls around the table such that no two boys are next to each other *?

ways. 5 girls can arrange among themselves in 5! ways. 5 boys can arrange among themselves in 5!

How many ways can 5 boys and 5 girls sit in a row?

120 ways, similarly for 5 girls, it is 5!. Thus, 5 boys and 5 girls can sit alternatively with a probability of 1/126.

How many ways can 5 boys sit in a row?

Now we have been given 5 boys. Now these 5 boys can be arranged in 5! Ways. Thus we have arranged 5 boys and 3 girls in 14400 ways in such a way that no 2 girls are together.

How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?

= 24 ways. Therefore, number of ways that 5 boys and 4 girls can be arranged in a row so that all boys stands together and all girls stand together = 2*120*24 = 5760. There are total (5 + 4) = 9 persons. They can be arranged on a beach in (9!)

How many different ways can 5 girls and 5 boys form a circle?

Problem Answer: There are 2,880 ways can 5 boys and 5 girls form a circle with boys and girls alternate.

How many different ways can 5 girls and 5 boys from a circle such that the boys and girls alternate?

2,880 ways
Therefore, there are 2,880 ways of forming a circle where 5 boys and 5 girls sit alternatingly.

What is the number of ways that 6 boys and 5 girls can be seated so that boys and girls alternate?

Hence, the answer is 86400.

How many ways can 5 persons be seated in a row inside the Theatre?

So there are 120 different ways to seat 5 girls in 5 chairs.

How many ways can five people be seated around a circular table if two of them insist on sitting beside each other?

So total possible ways = 9*8*7*6*5*4*3*2 = 9! = 362,880 ways.

How many ways can a conference of 4 boys and 4 girls be seated around a table so that boys and girls are alternate?

ways. = 144 ways. Therefore, the no. of ways in which 4 boys and 4 girls can be made to sit around a circular table such that no two boys sit adjacent to each other are 144 ways.

How many ways are there to seat six boys and two girls in a row of chairs so that two girls are separated?

× 2!= 6×15×24×2=4320 ways.

How many different ways can you seat 5 girls in 5 chairs?

Therefore they number of ways to seat 5 girls in 5 seats is: 5 × 4 × 3 × 2 × 1 ⇒ 20× 6 × 1 ⇒ 120 ×1 ⇒ 120 So there are 120 different ways to seat 5 girls in 5 chairs.

How many girls can be selected for the first seat?

There can 5 girls selected for the first seat. Then, there are 4 girls to select from for the second seat. Then, there are 3 girls to select from for the third seat. Then, there are just 2 girls to select from for the fourth seat. Then, there is just 1 girl for the fifth and final seat.

How many boys and girls sit alternative to each other?

Now, 5 boys and 5 girls sit alternative to each other. Suppose, let X be the place occupied by boy and ― is the place occupied by a girl. In either case, 5 boys can occupy the X marked places in 5!=120 ways, similarly for 5 girls, it is 5!. Now, 5 boys and 5 girls sit alternative to each other.

How many girls have to sit in the gap between 5 boys?

For boys and girls to occupy alternate positions, 5 girls has to sit in the gap between the 5 boys. What does Google know about me? You may know that Google is tracking you, but most people don’t realize the extent of it.