How many ways to select one specific book from 12 books?

It is desired that one specific book to be included in the sample of 5 books from 12 books. This mean we have choice of 4 books only to be selected from remaining 11 books. which is possible by 11C4 ways = 11*10*9*8/1*2*3*4 = 330 ways.

How many ways can you re-order a set of 5 books?

For each of those 10!5!, sets of 5 books, there’s 5! ways to order it, so one way to see the correct answer is to divide by the number of same re-orderings, and get 10!/5!5! 8 clever moves when you have $1,000 in the bank.

How many possibilities are there for the same set of books?

, First class degree mathematics. You have 10 possibilities for your first book, 9 for the second, and so on. So apparently that gives you 10x9x8x7x6 possibilities. But with that method of counting we can get the same set of books in a different order, in fact in every possible ordering.

What binomial number means “from 10 choose 5”?

We want the binomial number that means “from 10 choose 5” which is: 10!/ ( (10–5)! x 5!) But let me explain the reasoning behind this in layperson’s terms… First, how do you figure number of permutations? “Permutations” means the number of different combinations if order DID matter.

How many ways are there to order the different subjects books?

Now, you have to consider each individual subject’s books. For Math, there are 4 different books. That means there are 4! or 24 ways to order these books. Then, for Physics, there are 6! or 720 ways to order these books. And for Chemistry, there are 2! or 2 ways to order these books.

How many ways can you reorder a 5-book series?

Is If you’re counting each order you select books as a different “way.” For each of those 10!5!, sets of 5 books, there’s 5! ways to order it, so one way to see the correct answer is to divide by the number of same re-orderings, and get 10!/5!5! 8 clever moves when you have $1,000 in the bank.

How many choices are there for arranged books (from left to right)?

There are 5 choices for the left-most book. giving 5 ×4 = 20 choices for the first two books on the left. giving 5 ×4 × 3 = 60 choices for the first three books on the left. giving 5 ×4 × 3 × 2 = 120 choices for the first four books on the left. giving 5 ×4 × 3 × 2 × 1 = 120 choices for arranging the books (from left to right).