Guidelines

What happens to resistance when radius and length is doubled?

What happens to resistance when radius and length is doubled?

(a) Resistance of a wire is directly proportional to the length of a wire; so if the length is doubled, resistance is also doubled. Thus, if radius is doubled, area increases four times and hence the resistance becomes one-fourth.

What happened to the resistance of the wire when its length is increased to twice its original length?

Complete step-by-step answer: As the length of wire gets doubled, the cross-sectional area will become half of its previous value because volume of wire remains constant. Hence, we can see that the new resistance is four times the previous resistance.

READ:   Can you build immunity to snake venom?

How is the resistance of a wire affected if its length is doubled and radius is halved?

Errorless Physics NEET/AIIMS ( As resistance is directly proportional to length. So, with an increase in length resistance also increase. ) If the area is doubled then resistance gets halved of the original resistance. If the radius of doubled then resistance becomes 4 times the original resistance.

When the length of a conductor is doubled its resistance will be?

Hence, If the length of a wire is doubled, then its resistance becomes 2 times.

When the resistance of the conductor is doubled then the rate of flow of electric current is?

Inew = 6 mA (Current is directly proportional to voltage; a halving of the voltage will halve the current. But current is also inversely proportional to the resistance; a doubling of the resistance will halve the current.

What happens to the resistivity of a metal wire if you double its length and double its diameter?

READ:   Is attendance compulsory for MTech in IIT?

(d) Resistivity of wire remains constant. As the length of wire gets doubled, the cross-sectional area will become half of its previous value because volume of wire remains constant. Hence, we can see that the new resistance is four times the previous resistance.

When a wire of resistance 10 Ohm is stretched double to its length then its resistivity becomes?

So assuming it were possible to stretch a wire to double it’s length without crystallizing the metal to drastically alter its resistance or resistivity the resulting wire would be half as thick.

How is resistance related to length and radius?

Where R is the resistance of the conductor, L is the length of the conductor and A is the cross-sectional area of the conductor. So, we can say that the resistance of a wire is inversely proportional to the square of the radius of the wire.

When the length of a conductor is doubled then its resistance will be dash temperature and area of cross section remains constant?

READ:   Are Kirby vacuum cleaners any good?

Initial length of the conductor l1=l Final length of the conductor l2=2l Initial cross-sectional area A1=A Final cross-sectional area A2=2A The resistance of conductors given by R=ρ1A∝1A As both the length and area are doubled Hence, there will be no change in the resistance of the conductor and so it will remain …

What happens to the resistance of a conductor when the length of the conductor is reduced to half?

When length of conductor is halved, its resistance also gets halved.. Hope it helps Thanks…