What happens to the magnitude of the force F between two charges if the original distance is cut in half and the charge of one of the charges is doubled?

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

What happens to the force between 2 charges if the distance between them is cut by ¼?

Explanation: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.

What happens to the force between two charges if the distance between two charges is quadrupled?

The electric force between the point charges varies inversely with the square of the separation distance between the charges. Therefore, as the separation distance between the charges increases, the electric force between the charges decrease.

What happens to the force between two charges?

According to Coulomb’s law, the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. If the distance between two charges is reduced by half then the force between the two charges is quadrupled.

What happens to the force between two charges if you were to double the size of one charge?

Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.

When two charged particles are separated by a distance r the force between them is F if the distance between them is quadrupled the force between them is?

Explanation: The electrostatic force is inversely related to the square of the separation distance. So if d is four times larger (quadrupled), then F is 16 times smaller – that is, 1/16-th the original value.

What is the relationship between force and distance in an inverse square law?

The inverse square law tells us that the force on an object due to another is inversely proportional to the square of the distance between them.

What happens to the force when the distance is doubled?

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

How will the force between two charges change if the distance between them is trebled?

Explanation: The electrostatic force is directly related to the product of the charges and inversely related to the square of the separation distance. Tripling one of the charges would serve to triple the force. Tripling the distance would serve to reduce the force by a factor of nine.

What is the force between two small charged spheres having charges of 2?

Hence, force between the two small charged spheres is 6 × 10 – 3 N. The charges are of same nature. Hence, force between them will be repulsive.

What is the force applied between Q1 and q2?

q2 is positive (in case of like charges), the force F is positive and pushes the charges away from each other. The product q1. q2 is negative for unlike charges and the force F is negative. This means the objects are attracted to each other.

What is the force between two point charges separated by?

The force between two point charges separated by a certain distance is F . If each charge is double and the distance between them is also doubled then the force would be The force between two point charges separated by a certain distance is F. If each charge is double and the distance between them is also doubled then the force would be

What happens if the distance between two charges is halved?

So,if now force acting between the same charges is F The force between the two charges is quadrupled. The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant),

What is the equation for force between two electrical charges?

The equation for force between two electrical charges is as follows : F = (1/4pe)•q^2/d^2, where F is the force between the two charges (whether electroattractive or electrorepellant), 1/4pe is a constant incorporating pi (p), vacuum permissivity (e), q is the charge, and d is the distance in between the charges.

What is the formula for distance between two charges?

F = kq1q2 r2 (where, k is a constant, q1 and q2 are two charges separated by distance r) So,if the distance between the charges is halved, with no changes of the charges,new distance becomes r 2