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What is its velocity after 3 seconds?

What is its velocity after 3 seconds?

After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.

When a ball is thrown directly upward with initial velocity of 20 Metre per second what will be the maximum height it will reach and when will it be?

Thus, the greatest height reached by the ball is 20.39m .

What is the initial velocity of an object thrown straight up if it reaches a max height of 50 meters?

So if you throw the ball from a height of 50 m with an initial velocity of 30 m s−1 , it will decelerate under the influence of gravity until it comes to a complete stop at the top of its trajectory, i.e. at maximum height, then accelerate under the influence of gravity until it reaches the ground.

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What is velocity initial?

Therefore, the initial velocity is the velocity of the object before the effect of acceleration, which causes the change. After accelerating the object for some amount of time, the velocity will be the final velocity.

What is the maximum height reached by a ball if it is projected with an initial velocity of 4i 3j?

So, the maximum height reached by a ball is 0.45 meters. Hence, this is the required solution.

What is the velocity of a ball thrown straight up?

Its velocity is zero. Its acceleration is g (or -g, depending on the orientation of the vertical coordinate). Velocity is zero at the top most point.

When a ball is thrown straight up?

When a ball is thrown straight up with no air resistance, the acceleration at its highest point Group of answer choices is downward is zero is upward reverses from upward to downward reverses from downward to upward.

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What is the initial velocity of the ball thrown?

Ball A is thrown downward with an initial velocity of 6 m/s, while ball B is thrown straight upward with an initial velocity of 9.8 m/s. After one second has elapsed, the A. acceleration of ball A is upward B. velocity of ball B is zero.

What is the average velocity of a moving object after 2 seconds?

The average vertical velocity is 10m/s so at 2 seconds it has reached 20m high. The horizontal velocity is 25 m/s so after 2 seconds → 50 metres. It is at x = 50, y = 20 and travelling horizontally at 25 m/s. Equations? If your g is not 10 m/s per second the numbers will be much messier (for a start it wo

What is the maximum height of a ball thrown vertically upwards?

or H= v1 2/2g (equation of maximum height) ………. (iv) Therefore if a ball is thrown vertically upwards with 98 m/s velocity, the maximum height reached by it would be = (98 x98 )/(2 x 9.8) meter = 490 meter.

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What is the average deceleration of the ball at the highest point?

So to go from 20 m/s to zero, will take two lots of zero to 10 in reverse, thats 2 seconds, average speed of 5 m/s and 15 m/s, for each second respectively, thats a total average of 20 metres per second deceleration over two seconds for a total average speed of 20 m/s Speed of the ball at the highest point is zero m/s.