What is the acceleration due to gravity on the surface of a planet whose mass and radius are half of earth value of g on the surface of the earth is 9.8m S * 2?

As we know that the acceleration in earth is calculated by the formula (Gm)/(r^2) which equals 9.8m/s^2 where m is the mass of the earth and r is the radius of the earth. so, the value of g on that planet will be 19.6m/s^2.

What would be the acceleration due to gravity on another planet whose mass and radius are twice that of the earth?

the acceleration due to gravity will be reduced if the mass and the radius of a planet are doubled. so acceleration due to gravity is divide in the same ratio.

What would be the acceleration due to gravity on the surface of a planet?

Acceleration due to gravity at the earth’s surface is 10ms−2.

What is the acceleration due to gravity at the center of Mars A 0 B 5 C 6 D 9?

Hence, acceleration due to gravity (g) on Mars is 3.7 m/s².

What is the acceleration due to gravity at a height R 5 from the surface of the earth?

Acceleration of the body is 0.0042 m/s² . Thus,acceleration due to gravity at a height R/5 from the surface of earth is 6.8m/s².

When you move from equator to pole What is the value of acceleration due to gravity?

Answer Expert Verified The acceleration due to gravity at the equator is 9.78 m/s2, whereas the acceleration due to gravity at the poles is 9.83 m/s2.

What is dimension of gravitational constant?

The dimension of the gravitational constant G is M−1L3T−2.

What is the acceleration due to gravity on the surface of the moon?

The acceleration due to gravity on the surface of the Moon is approximately 1.625 m/s2, about 16.6\% that on Earth’s surface or 0.166 ɡ. Over the entire surface, the variation in gravitational acceleration is about 0.0253 m/s2 (1.6\% of the acceleration due to gravity).

What is acceleration due to gravity on Mars?

It also has a mean radius of 3,390 km, which works out to 0.532 Earth radii. The surface gravity of Mars can therefore be expressed mathematically as: 0.107/0.5322, from which we get the value of 0.38. Based on the Earth’s own surface gravity, this works out to an acceleration of 3.724 meters per second².

How do you find the acceleration due to gravity on Mars?

The surface gravity of Mars can therefore be expressed mathematically as: 0.107/0.532², from which we get the value of 0.376. Based on the Earth’s own surface gravity, this works out to an acceleration of 3.711 meters per second squared.

Who found the value of universal gravitational constant?

Lord Henry Cavendish
The constant of proportionality in this equation is G – the universal gravitation constant. The value of G was not experimentally determined until nearly a century later (1798) by Lord Henry Cavendish using a torsion balance.