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What is the area of a triangle with vertices at − 2 1 2 1 and 3/4 enter your answer in the box?

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What is the area of a triangle with vertices at − 2 1 2 1 and 3/4 enter your answer in the box?

The area of a triangle with vertices at (-2, 1), (2, 1), and (3, 4) is 6 sq. units.

What is the 3 vertices of a triangle?

Each side of a triangle has two endpoints and the endpoints of all three sides are intersected possibly at three different points in a plane for forming a triangle. The three different intersecting points of them are called vertices of a triangle.

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Why is the area of a triangle 1 2bh?

A diagonal of a rectangle separates the rectangle into two congruent triangles. The area of each triangle is one-half the area of the rectangle. So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

What is the area of the triangle?

The area of each triangle is one-half the area of the rectangle. So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

How do you find the area of a triangle with given vertices?

The formula for the area of the triangle is given by S=12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)] , where, (x1,y1),(x2,y2),(x3,y3) are the coordinates of the three vertices of the triangle. The units of the area are assumed to be square units.

How do you find the area for a triangle?

The area of each triangle is one-half the area of the rectangle. So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle. Example: Find the area of the triangle.

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What is the area of a triangle with vertices -3?

The area of a triangle with vertices (-3,0), (3,0) and (0,k) is 9 sq. units.

How to find the area of a triangle using its coordinates?

We have a formula which can be directly used on the vertices of triangle to find its area. If, (x1, x2), (x2, y2) and (x3, y3) are the coordinates of vertices of triangle then Area of Triangle = Now, we can easily derive this formula using a small diagram shown below.

What is the area of triangle ABC with three points?

In other words, three points A (x1, y1), B (x2, y2) and C (x3, y3) are collinear, if any one of these points lies on the straight line joining the other two points. Suppose that the three points A (x1, y1), B (x2, y2) and C (x3, y3) are collinear, then they can not form a triangle. So, the area of triangle ABC is equal to zero.

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What are the coordinates of the vertices of a trapezium?

Let the coordinates of vertices are (x1, y1), (x2, y2) and (x3, y3). We draw perpendiculars AP, BQ and CR to x-axis. = Area of Trapezium ABQP + Area of Trapezium BCRQ – Area of Trapezium ACRP