What is the equation of the line that passes through the point 3 3?

Any line perpendicular to the given line 2y + 3x = 0 is 3y – 2x = c (c is a constant). Since it passes through the point (3, 3), therefore, we must have; 3.3 -2.3 = c or c = 3 . Hence the required line is 3y -2x = 3. The line 2x+3y=0 has slope , so any line perpendicular to it will have slope .

How do you find the equation of a line that passes through a point?

How to Find the Equation of a Line from Two Points

1. Find the slope using the slope formula.
2. Use the slope and one of the points to solve for the y-intercept (b).
3. Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.

What is an equation of the line that passes through 3 1?

y=mx+b becomes 1=3⋅13+b .

How do you find the equation of a straight line?

The general equation of a straight line is y = mx + c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis. The equation of a straight line with gradient m and intercept c on the y-axis is y = mx + c.

What is the equation of the line that passes through the point (- 4 2 and has a slope of?

y = 1/2 x + 4 Final answer! We have the point ( -4 , 2 ) so x1 = -4 and y1 = 2. The slope is still 1/2 so m = 1/2.

What is the equation of a line that passes through the points 1/3 and 2 5?

y = 2x + 1 this is slope-intercept form. 2x – y = -1 this is standard form.

How do you find the x intercept of a straight line?

Let P ( x, y) be any point on the given line l. Let a be the X-intercept of the straight line, so the line must pass through the point A ( a, 0). Take a as the X-intercept of the straight line so the line must pass through the point A ( a, 0), i.e. O A = a = X-intercept. From point P draw P Q perpendicular to the X -axis.

y = m ( x – a) This is the equation of a straight line having the slope m and X-intercept a. NOTE: It may be noted that if the line passes through the origin ( 0, 0), then the X-intercept is equal to zero, i.e. a = 0, so the equation of the straight line becomes y = m x.

How do you find the equation of a line in point form?

The formula for slope is m = y2 − y1 x2 − x1, where m represents slope, ( x2,y2) and ( x1,y1) represent separate points. Let point 1 be (2, 3) and point 2 (4,0). Now that we know the slope we can use point slope form to find the equation of our line.