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What is the equation of the quadratic graph with a focus of 4 3 and a Directrix of y =- 6?

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What is the equation of the quadratic graph with a focus of 4 3 and a Directrix of y =- 6?

What is the equation of the quadratic graph with a focus of (4, 3) and a directrix of y = -6? Summary: The equation of the quadratic graph with a focus of (4, 3) and a directrix of y = -6 is (x – 4)2 = 18[y + (3/2)].

What is the equation of parabola?

The general equation of parabola is y = x² in which x-squared is a parabola. Work up its side it becomes y² = x or mathematically expressed as y = √x. Formula for Equation of a Parabola. Taken as known the focus (h, k) and the directrix y = mx+b, parabola equation is y−mx–b² / m²+1 = (x – h)² + (y – k)² .

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How do you find the equation for a parabola?

How to find a parabola’s equation using its Vertex Form

  1. Step 1: use the (known) coordinates of the vertex, (h,k), to write the parabola’s equation in the form: y=a(x−h)2+k.
  2. Step 2: find the value of the coefficient a by substituting the coordinates of point P into the equation written in step 1 and solving for a.

What is the equation of a parabola?

Parabola Equation The general equation of a parabola is: y = a(x-h)2 + k or x = a(y-k)2 +h, where (h,k) denotes the vertex. Directrix: The line drawn parallel to the y-axis and passing through the point (-a, 0) is the directrix of the parabola. The directrix is perpendicular to the axis of the parabola.

What is the equation of Directrix of parabola?

The axis of the parabola is y-axis. Equation of directrix is y = -a. i.e. y = -½ is the equation of directrix. Vertex of the parabola is (0,0).

What is the equation of the quadratic graph with a focus?

If you have the equation of a parabola in vertex form y=a(x−h)2+k, then the vertex is at (h,k) and the focus is (h,k+14a). Notice that here we are working with a parabola with a vertical axis of symmetry, so the x-coordinate of the focus is the same as the x-coordinate of the vertex.

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What is the equation of the quadratic graph with a focus of 5/6 and a Directrix of Y 2?

Answer: The equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2 is x2 -10x – 8y + 57 = 0.

What is the equation of focus in parabola?

How do you find the equation of a focus?

In order to find the focus of a parabola, you must know that the equation of a parabola in a vertex form is y=a(x−h)2+k where a represents the slope of the equation. From the formula, we can see that the coordinates for the focus of the parabola is (h, k+1/4a).