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What is the initial velocity of a car that starts from rest?

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What is the initial velocity of a car that starts from rest?

0 m/s
Answer and Explanation: The car starts initially from rest so it’s initial velocity u0=0 m/s u 0 = 0 m / s .

What is the final velocity of the cars?

The final velocity of the car will be 40 m/s.

What is the acceleration of a car that travels?

Ch. If an object’s velocity is constant, however, its acceleration will be zero. Since acceleration = (change in velocity)/(time it takes), if the change in velocity = 0, the acceleration = 0, too. Light’s acceleration is zero. Since it travels in a straight line, its direction does not change.

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How do you find the final velocity of a car?

How do you find final velocity?

  1. Work out which of the displacement (S), initial velocity (U), acceleration (A) and time (T) you have to solve for final velocity (V).
  2. If you have U, A and T, use V = U + AT.
  3. If you have S, U and T, use V = 2(S/T) – U.
  4. If you have S, A and T, use V = (S/T) + (AT/2).

What is the acceleration of a car that travels in a straight line at a constant speed of 50 m s?

zero acceleration
Explanation: Acceleration is defined as the rate of change of velocity. In the given problem the car travels in a straight line at a constant speed. Or there is zero acceleration of the car.

What is the final velocity of an object with acceleration?

We have u = o (as the object starts from rest), t = 5 sec., and acceleration a = − 1.5 m sec2. Hence final velocity v = −1.5 ×5 = − 7.5 m sec.

What is the average velocity of a car starting from rest?

A car starting from rest accelerates at a constant rate of 3.0 m/s2 for 8.0 seconds. How far does the car travel during this time? You can also think about it this way. With constant acceleration, the average velocity will occur at the midpoint of the time or (1/2) (8.0 sec) (3.0 m/sec^2) or 12 m/sec.

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What is the speed of the car when the brakes are applied?

Acar travels with a uniform velocity of 20ms −1 for 5 sec. The brakes are then applied and the car is uniformly retarded. It comes to rest in further 8 sec. by drawing a graph between velocity and time-find. The distance traveled in the first 5 sec. The distance traveled after the brakes are applied. Total distance traveled.

How does an object come to rest in further 8 seconds?

It comes to rest in further 8 sec. by drawing a graph between velocity and time-find. The distance traveled in the first 5 sec. The distance traveled after the brakes are applied. Total distance traveled. (4) Acceleration during the first 5 sec= 0, because uniform velocity.