What is the maximum height the ball will reach?

Therefore, at maximum altitude the velocity of the ball must be zero. Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s….Objects Launched Upward.

Variable	Value
Δy	FIND
a	-9.8 m/s2
t	0.40 s

How much high above the ground a person can throw a ball if he is able to throw the same ball up to maximum horizontal distance of hundred Metre?

or h=u22g=12×60=30m.

How much high above the ground a man can throw the same ball up to maximum distance of 60m?

Explanation: The horizontal range is maximum (R-max) when the angle of projection is 45 degree. Thus, the maximum height till which the boy can throw the ball is 25 m.

What is the horizontal displacement range of the ball?

This is consistent with the initial horizontal velocity of 20 m/s. Thus, the horizontal displacement is 20 m at 1 second, 40 meters at 2 seconds, 60 meters at 3 seconds, etc….

Time	Horizontal Displacement	Vertical Displacement
1 s	20 m	-4.9 m
2 s	40 m	-19.6 m
3 s	60 m	-44.1 m
4 s	80m	-78.4 m

What is the maximum height?

Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point – and it’s falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0).

Can throw a ball to a maximum horizontal distance of 50m?

Solution 1. The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45°, i.e., θ = 45°. The ball will achieve the maximum height when it is thrown vertically upward.

What is the maximum vertical height to which a cricketer can throw a ball?

Cricketer can throw a ball to maximum vertical height of \( 80\;m\).

What is the formula for the maximum horizontal range?

The range R (in the horizontal direction) is given as: R=v0⋅T=v0√2Hg R = v 0 ⋅ T = v 0 2 H g .