What is the percentage error in the measurement of kinetic energy if percentage errors in mass and speed are 2\% and 3\% respectively *?

Percentage error in the measurement of mass and speed are 2\% and 3\% respectively. The error in the measurement of kinetic energy obtained by measuring mass and speed will be. ∴\% error in K= (\% error in m) +2(\% error in v).

What is the maximum percentage error in density of a body if percentage error in measurement of mass is 4\% and percentage error in measurement of side is 5\%?

Answer: Thus, the maximum possible percentage error in the relative density of the material of the body is 11\%.

What is the maximum percentage error in measurement of kinetic energy if the percentage error in mass and speed are 1\% and 2\% respectively?

Answer: Maximum percentage error is 8\%.

What will be the error in the measurement of kinetic energy if error in measuring momentum is 100?

Hence the answer is 200\%

What is the percentage error in kinetic energy?

The percentage error in energy is 1.3\%.

What is the percentage error in the measurement of the kinetic?

Answer: So error\% in kinetic energy=1/2m((1.5v)^2)-1/2 mv^2 /(1/2mv^2) ×100 2.25v^2-v^2 /v^2 =1.25×100=125\%. This should be identified with error and positive errors are taking place in right measurement of the body.

When the percentage error in the measurement of mass and velocity?

When percentage errors in the measurement of mass and velocity are 1\% and 2\% respectively, the percentage error in K.E. is 5\%.

What is the maximum percentage error in the density?

Therefore, relative error in density is 0.09, which is equal to 9\%, which is the maximum error.

When percentage errors in the measurement of mass and velocity are 1\% and 2\% respectively the percentage error in Ke is 5\%?

Assertion: When percentage error in the meansurement of mass and velocity are 1\% and 2\% respectively the percentagwe error in K.E. is 5\%. Reason: (Delta K)/(K) = (Delta m)/(m) = (2 Delta v )/(v). If both Assertion and Reason are correct and Reason is the correct explaination of Assertion.

Is the error in measurement of momentum of a particle is 10\% and mass is known exactly the permissible error in the determination of kinetic energy is?

If the error in measurement of momentum of a particle is 10\% and mass is known exactly, then what is the permissible error in? – Quora. Short answer would be 21\% error.

What will be the error in measurement of kinetic energy?

During measurement of kinetic energy T , The percentage error in meansurment of mass of particle and momentum of particle are 2\% and 3\% respectively .

What is the percentage error in the measurement of the kinetic energy of a body if there is an error of 5\% in the velocity of the body and 10\% in the mass of the body?

Answer: So error\% in kinetic energy=1/2m((1.5v)^2)-1/2 mv^2 /(1/2mv^2) ×100 2.25v^2-v^2 /v^2 =1.25×100=125\%.

What is maximum percentage error in the calculated value of kinetic energy?

If the percentage error in the measurement of momentum and mass of an object are 2\% and 3\% respectively, then maximum percentage error in the calculated value of its kinetic energy is (1) 2\% (2) 1\% (3) 5\% (4) 7\% proconted by X = Maj b 47.

What is the percentage error in the measurement of mass and speed?

The percentage error in the measurement of mass and speed are 2 \% and 3 \% respectively. The error in the estimate of kinetic energy obtained by measuring mass and need will be

What is the relative percentage error in density of a sphere?

If the measured mass of the sphere has a relative error of 2\%, the relative percentage error in the density is In an experiment, mass of an object is measured by applying a known force on it, and then measuring its acceleration.

How to measure the mass of an object in an experiment?

In an experiment, mass of an object is measured by applying a known force on it, and then measuring its acceleration. If, in the experiment, the measured values of applied force and the measured acceleration are F = 1 0. 0 ± 0. 2 N and a = 1. 0 0 ± 0. 0 1 m / s 2, respectively, the mass of the object is