What is the probability of getting 2 red balls?

On your first pick, the probability is 11/16 that you choose a red ball. On the second pick, the probability is 10/15 that you choose a red ball. So 11/16*10/15 = 110/240 = 45.83\% chance of picking two red balls in a row.

What is the probability that both balls are green?

As the first pick and second pick of the bag are independent events, the probability of picking two green balls is equal to 1/2 * 4/9. By multiplying the denominators together and the numerators together, the probability is found to be 4/18 or 2/9.

What is the probability that all balls are red?

Therefore the probability of getting a red ball or a white ball is 4/5. Therefore the probability of getting a black ball or a white ball is 11/20. Therefore the probability of getting exactly one red ball is 99/190. Therefore the probability of getting at most one red ball is 77/95.

How many ways are there to pick 3 red balls out of the jar assume that the order you pick the balls out does not matter but it does matter which 3 red balls you pick?

There are a total of (123) different ways of choosing 3 balls.

What is the probability that the two balls are of a different color?

The probability of taking two balls of different colors is P(15/56).

What is the probability of picking 2 balls of the same color?

The probability that both balls are the same color is 0.44.

What is the probability of picking green marbles?

0
The probability of selecting a green marble at random from a jar that contains only green, white and yellow marbles is 0.

What is the and/or rule in probability?

When events are mutually exclusive and we want to know the probability of getting one event OR another, then we can use the OR rule. P(A or B) = P(A) + P(B) for mutually exclusive events.

What is the probability that the balls drawn contain different colors?

A bag contain 2 red balls, 6 yellow balls and 4 green balls. If 3 balls are drawn randomly, then what is the probability that the balls drawn contain balls of different colors? = 48. = 12 / 55. A bag contain 2 red balls, 6 yellow balls and 4 green balls.

How many balls can be selected from remaining 12 4?

Rest 1 ball can be selected from remaining ( 12 – 4 ) = 8 balls in 8 C 1. = 42 / 55. A bag contain 2 red balls, 6 yellow balls and 4 green balls. If 3 balls are drawn randomly, then what is the probability that the balls drawn contain no yellow ball?

How many white balls are in a bag of random balls?

A bag contains 8 white balls and 6 black balls. If we taken out two random balls from that bag, then find the probability that they are of the same color? Here S be the sample space. therefore, 91.

What is the probability without replacement of two Reds?

without replacement (dependent events), P(two reds) =3/6×⅖=⅕ Probability Without Replacement Let’s assume we have a jar with 10 green and 90 white marbles.