What is the probability that 2 digit number selected at random will be a multiple of 3 and not a multiple of 5?

Probability that a two-digit number is a multiple of 3 and not a multiple of 5 = 30-6 = 2490= 415. Find the probability that a number selected at random from the numbers 1, 2, 3., 34 , 35 is (a) a prime number, (b) a multiple of 7, (c) a multiple of 3 or 5.

What is the probability of selecting a two digit number at random such that it is a multiple of 2 but not a multiple of 14?

Hence, the required probability is 24/90 = 4/15.

What is the probability of that number being 17?

1/90 is your answer.

What is the probability that a factor of 30 is a two digit number?

therefore probability is 3/8.

What is the probability that a randomly chosen 2 digit number is divisible by 3?

Thus there are 90 such numbers. Since out of these 30 numbers are multiple of 3 therefore the probability that a randomly chosen positive 2-digit integer is a multiple of 3 is 30/90 = 1/3.

What is the probability of two digits being same?

Therefore, 1/10 is the probability of both the digits being same.

What is the probability that a two digit number is divisible by 15?

⇒ n(S) = 90. Let ‘A’ be the event of getting a number divisible by 15. ∴ The probability of getting a number divisible by 15 = 115 .

What is the probability of both digits being the same?

What is the probability of one of the digit being 1?

Answer: (a) 90 two digit number are there. p(one of the digit being 1)=10/90=1/9.

What is P factor of 30?

The factors of 30 are the numbers that divide 30 exactly without leaving a remainder. As the number 30 is an even composite number, it has factors other than 1 and 30. Thus, the factors of 30 are 1, 2, 3, 5, 6, 10, 15 and 30.

What is the probability that a random 2 digit number is a multiple of 7?

The two digits multiples of 7 are 14, 21, 28,….., 98. There are 90 two digits numbers. ∴ Required probability =1390.

What is the probability that a randomly chosen two digit positive integer is a?

(b) 2-digit positive integers are 10, 11, 12, , 99. Thus, there are 90 such numbers. Since out of these, 30 numbers are multiple of 3, therefore, the probability that a randomly chosen positive 2-digit integer is a multiple of 3, is 30/90 = 1/3.

What is a random number between 1 and 20?

A random digit from 1 to 9 (inclusive) is chosen, with all digits being equally likely. The probability that when it’s squared it will end with the digit 1. 2.) A random number between 1 and 20 (inclusive) is A 4-digit number is selected from the numbers {1,2,3,4,5,6} where the digits are selected without replacement.

What is the probability of a 2 digit odd multiples of 5?

Multiples of 5 have last digits of 5 or 0. An odd 2 digit is one where the last digit is either 1,3,5,7 or 9. Therefore there are 9 digits in the 2nd slot x 5 numbers in the 1st slot = 45 odds. There are 99–76 + 1 = 24 numbers larger than 75. Therefore the probability is 24/90.

What is the probability of having a prime number between 2-100?

There are 25 Prime numbers between 2–100. 1 is not considered to be a prime. so that leaves a number set of 2–99 or 25 Prime and 73 non Prime or 98 number in total numbers. So the probability would be 25/98 or 25.5\%. , Analyst programmer for years, but I love mathematics.

How many integers are randomly selected from 1 to 10?

Four integers are randomly selected from the natural numbers from 1 to 10. If the possibility that there are atleast two successive numbers and there are exactly three successive numbers among those 4, selected are a and b respectively, then A bag contain 4 red balls, 6 yellow balls and 5 green balls.