What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 *?

Probability of getting a number which is a multiple of 3 or 5 = 9/20..

What is the probability that the ticket drawn has a number which is a multiple of 3 or 7?

Thus the required probability is equal to favourable outcome by total number of tickets. Thus required probability = \[\dfrac{8}{{20}} = \dfrac{2}{5}\]. Thus we got the required probability as, \[\dfrac{2}{5}\]. Thus the probability that the ticket drawn has a number which is a multiple of 3 or 7 = \[\dfrac{2}{5}\].

Why are tickets numbered?

Concert, raffle, movie, and theater tickets are kinds of tickets that need to have a number. Ticket numbers function like an identification card. The ticket should always be with its owner because that is a person’s proof that they paid for a concert or movie, or the owner of a winning ticket.

What is the probability of multiple of 3 but not of 9?

What can be said is that in any finite initial segment of the natural numbers {1,…,n}, if we have a uniform distribution on its numbers, approximately 2/3 of the multiples of 3 will not be multiples of 9. I say “approximately” because the probability will be slightly higher for many values of n.

What is the probability that the number is a multiple of 3?

∴ P (a multiple of 3) = 2/6 = 1/3.

How many numbers between 11 and 111 are the multiples of both 2 and 5?

20, 30, 40, 50, 60, 70, 80, 90, 100, 110 are the numbers divisible by both 2 and 5. So, there are 10 numbers in between 11 and 111 that are divisible by both 2 and 5.

What is the probability that a leap year will have 53 Sundays?

The probability that a leap year selected at random contains 53 Sunday is (1)7/366 (2)28/183 (3) 1/7 (4) 2/7. We know that a leap year has 366 days. So, we have 52 weeks and 2 days. Hence, a leap year has 52 Sundays.

What is the probability that a non leap year has 53 Sundays?

1/7
Answer: The probability of getting 53 Sundays in a non-leap year is 1/7.

What is the probability of getting a prime number from 1 to 25?

Hence, the Probability of getting a prime number from 1 to 25,P(E) is 9/25. HOPE THIS ANSWER WILL HELP YOU….

What is the probability of getting a multiple of 3 from 1 to 20?

Complete step-by-step answer: Numbers on the card are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20. Now, let us find the probability of getting a multiple of 3. Multiple of 3 between 1 to 20 are 3, 6, 9, 12, 15, 18.

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