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What is the radius of circle whose equation is x2 y2 6x 4y 12 0?

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What is the radius of circle whose equation is x2 y2 6x 4y 12 0?

i.e, √(-3)2+(2)2-(-12)=√25 or 5.

How do you find the equation of a circle?

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

What is the general form of the equation of the given circle with center A?

We know that the general equation for a circle is ( x – h )^2 + ( y – k )^2 = r^2, where ( h, k ) is the center and r is the radius. So add 21 to both sides to get the constant term to the righthand side of the equation. Then complete the square for the y terms.

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What is the radius of a circle whose equation is x2 y2 8x − 6y 21 0?

5units
The radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0 is 5units.

What are the center and radius of the circle defined by the equation x2 y2 6x 4y 4 0?

The center is =(3,−2) and the radius is =3. graph{(x^2+y^2-6x+4y+4)=0 [-14.08, 8.11, -5.51, 5.58]} Nam D. Jul 5, 2018.

How do you find the radius of a circle with an equation?

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”. This form of the equation is helpful, since you can easily find the center and the radius.

How do you find an equation?

Steps to find the equation of a line from two points:

  1. Find the slope using the slope formula.
  2. Use the slope and one of the points to solve for the y-intercept (b).
  3. Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.
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How do you solve a circle equation in standard form?

The standard form of a circle’s equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius. To convert an equation to standard form, you can always complete the square separately in x and y.

What is the standard form of the equation of a circle with center 3 − 2 and radius 4?

(x+3)2+(y+4)2 = 9. This is the equation of our given circle, in standard form.

How do you find the equation of a circle with center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2. Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation. Example: Say point (1,2) is the center of the circle and radius is equal to 4

What is the formula to find the radius of a circle?

Therefore, the radius of a circle is CP. By using distance formula, (x-h) 2 + (y-k) 2 = CP 2. Let radius be ‘a’. Therefore, the equation of the circle with centre (h, k) and the radius ‘ a’ is, (x-h) 2 +(y-k) 2 = a 2. which is called the standard form for the equation of a circle. Equation of a Circle in General Form

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How do you find the equation of a circle in standard form?

It is the same idea as before, but we need to subtract a and b: (x−a) 2 + (y−b) 2 = r 2. And that is the “Standard Form” for the equation of a circle! It shows all the important information at a glance: the center (a,b) and the radius r.

How to find the equation of a circle in AutoCAD?

1 Step 1: Enter the circle centre and radius in the respective input field 2 Step 2: Now click the button “Find Equation of Circle” to get the equation 3 Step 3: Finally, the equation of a circle of a given input will be displayed in the new window More