What is the smallest number when divided by 28 and 32?

The smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively:- 28 – 8 = 20 and 32 – 12 = 20 are divisible by the required numbers. Therefore, the required number will be 20 less than the LCM of 28 and 32. Prime factorization of 28 = 2 x 2 x 7 Prime factorization of 32 = 2 x 2 x 2 x 2 x 2

How do you find the remainder when dividing by 10?

First, if a number is being divided by 10, then the remainder is just the last digit of that number. Similarly, if a number is being divided by 9, add each of the digits to each other until you are left with one number (e.g., 1164 becomes 12 which in turn becomes 3), which is the remainder.

Which number is 20 less than the LCM of 28 and 32?

28 – 8 = 20 and 32 – 12 = 20 are divisible by the required numbers. Therefore, the required number will be 20 less than the LCM of 28 and 32. LCM (28, 32) = 2 x 2 x 2 x 2 x 2 x 7 = 224. Therefore, the required the smallest number = 224 – 20 = 204. Verification: 204/28 = 28 x 7 = 196.

What is the remainder when 821 is divided by 4?

There are 3 ways of writing a remainder: with an R, as a fraction, and as a decimal. For example, 821 divided by 4 would be written as 205 R 1 in the first case, 205 1 / 4 in the second, and 205.25 in the third. What is the remainder when 26 is divided by 6?

What is the least possible positive integer that can divide 2884?

When we divide 2884 by any of 12, 16, 18 or 30, we get the remainder as 4 and 7 completely divides 2884. This is the least possible positive integer. Therefore, the required answer is 2884. 720×3+4 = 2164……”

What is the least value of (N-4) with k = 4?

So, we can say (N-4) is completely divisible by 12, 16, 18 and 30. But N should be completely divisible by 7. Thus, general form of N can be taken as: Now, for k = 4, N = 2884 which is completely divisible by 7. Thus, the least value of N is 2884. (Answer) The answer is 2884 . 8 clever moves when you have $1,000 in the bank.

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What is the least number which when divided by 6 15 and 18?

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case. Let us check our answer.

Which number has a remainder of 25 when divided by 35?

Find the least number which when divided by 15, leaves a remainder of 5, when divided by 25, leaves a remainder of 15 and when divided by 35 leaves a remainder of 25. Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15.