What is the smallest number which when divided by 15 25 and 35 leaves a remainder of 5 in each case?

The Brainliest Answer! 425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425.

What is the smallest number which is divisible by 15 and 20 without a remainder?

5 is the smallest number which is divisible by 15 and 20.

What is the smallest number which when divided by 14 21 and 35 leaves a remainder of 2 in each case?

The LCM is 210.

What is the smallest number that leaves a remainder of 5 each when divided by 15 and 18?

Answer: 95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case. To find the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case we have to do the following steps: Find the LCM of 6, 15 and 18. Add 5 to the LCM.

What is the least number which when divided by 15?

Now, we will find the L.C.M. of 15, 25 and 35 by the fundamental theorem of arithmetic in which first we express any number in terms of multiplication of prime numbers. Then, we will find the value of the least common multiple (L.C.M). Thus, the 515 is the required number. Hence, (a) is the correct option.

What is the least number which when divided by 15 18 and 36?

∴ The required number is 1089.

What is the smallest number which when divided by 20 25 35 and 40?

Therefore, the smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is 1394.

What number has a remainder of 5 when divided by 15?

So the answer is: 5, which is the smallest number that has a remainder of 5 when divided by 15, 20, and 35. We can find other larger integers that have a remainder of 5 when divided by 15, 20, and 25. Using the J programming language, we can search all the integers up to 500:

What is the smallest number that when divided by 35 leaves 7?

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647. Answer verified by Toppr Upvote (0) Was this answer helpful?

What is the smallest number when divided by 35 56 and 91?

What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in each case? What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in each case? The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

How to find the smallest number evenly divisible by first n numbers?

Smallest number divisible by first n numbers. Given a number n find the smallest number evenly divisible by each number 1 to n. Examples: If you observe carefully the ans must be the LCM of the numbers 1 to n. Initialize ans = 1. Iterate over all the numbers from i = 1 to i = n. At the i’th iteration ans = LCM(1, 2, …….., i).