What is the sum of the digits divisible by 9?

Likewise forthe ninth digit, the sum of the digits 1,2,..9=45 which is divisible by9. In order for a number to be divisible by 5, it must end in 0 or 5. Sincethere is no 0 allowed, the fifth digit must be 5 in order for 5 divide intoit.

What is the largest 7 digit number divisible by 11?

90909 * 11 is the smallest number 7 digit number divisible by 11 909090 * 11 is the largest 7 digit number divibsle by 11. So there are precisely 818181 such numbers.

What is the 5th digit of a number divisible by 5?

In order for a number to be divisible by 5, it must end in 0 or 5. Since there is no 0 allowed, the fifth digit must be 5 in order for 5 divide into it.

How many digits are there in a nine digit number?

Problem: Nine Digit Number. A nine-digit number is formed using each of the digits 1,2,3,…,9 exactly once.

Is abc-cba divisible by 18?

So, all the numbers which are the factors of 99 will also be divisible by abc-cba Here, 9, 11 and 33 are the factors of 99. But 18 is not a factor of 99. Hence abc- cba is not divisible by 18. 5. The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by

What is the rule for divisibility by 8?

This tells us that the other four positions must be filledby the odd digits. Therefore, the third digit must be odd and 4 must dividethe third and fourth digits together according the rule for divisibilityby 4. Similarly, the sixth, seventh and eighth digits together must be divisibleby eight according to the rule for divisibility by eight.

What is the sum of the digits in the divisibility test?

Given that, the sum of the digits xyz is given as x+y+z is 6, where z is an odd integer. The divisibility test of 3, the number xyz is divisible by z. Since the last digit is an odd digit, then xyz is an odd multiple of 3.