What is the sum of the reciprocals of 50?

50 is divided into two parts such that the sum of their reciprocals is 1/ 12. Find the two parts? – Quora 50 is divided into two parts such that the sum of their reciprocals is 1/ 12. Find the two parts?

What are the two parts in which 50 is divided?

Therefore the two parts in which 50 is divided are 30 and 20. The sum of two numbers is 2 and the sum of their reciprocals is 2.25. What is the number? Let the numbers be x and y.

What is 1818 taken away from 8 times of a number?

18 is taken away from 8 times of a number is 30. Find the number. Let ‘x’ be the number. Add 18 to both sides. Divide both sides by 8. So, the number is 6. The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes 3/4.

What is the sum of the first 3 digits of a number?

A number consists of three digits of which the middle one is zero and the sum of the other digits is 9. The number formed by interchanging the first and third digits is more than the original number by 297.Find the number. A manufacturer produces 80 units of a product at a cost of $22000 and 125 units at a cost of $28750.

How do you calculate the minimum difference between two arrays?

Efficient Approach: To optimize the above approach, the idea is to calculate the total sum of the array elements. Now, iterate over the array and calculate the prefix sum of the array and find the minimum difference between the prefix sum and the difference between total sum and the prefix sum for any index of the array, i.e.,

What is the value of DP [n+1] [sum+1}?

Let dp [n+1] [sum+1] = {1 if some subset from 1st to i’th has a sum equal to j 0 otherwise} i ranges from {1..n} j ranges from {0.. (sum of all elements)} So dp [n+1] [sum+1] will be 1 if 1) The sum j is achieved including i’th item 2) The sum j is achieved excluding i’th item. Let sum of all the elements be S.

How to solve the sum+1 problem in dynamic programming?

The problem can be solved using dynamic programming when the sum of the elements is not too big. We can create a 2D array dp [n+1] [sum+1] where n is the number of elements in a given set and sum is the sum of all elements. We can construct the solution in a bottom-up manner. The task is to divide the set into two parts.

The sum of their reciprocals is 1/12. 50 is divided into two parts such that the sum of their reciprocals is 1/12. The numbers will be 20 and 30.

What is the sum of two parts of 50?

50 is divided into two parts such that the sum of their reciprocal is 1/12.find the two parts . See what the community says and unlock a badge. 50 is divided into two parts. 50 is divided into two parts. The two parts are 30 and (50-x) = 20.

What is (1/(50-x))+(1/x) = 1/12?

Let 50 be divided into two parts such that one of the part be x and the other part thus be (50-x). Hence 50=50-x+x. As per the given question, (1/ (50-x))+ (1/x)=1/12.