What is the total distance of a vertically thrown ball?

(You could also see this by noting that it is the same as the downward motion except for the initial 6 m fall.) The total distance is 24 + 18 = 42 m. A vertically upward thrown ball rises to a height of 8 m and bounces. After each bounce, it rises to 3/4 of the height of the previous bounce.

What is the height of the ball when it bounces?

A ball is dropped from a height of 10 feet and bounces. Each bounce is ¨ú of the height of the bounce before. Thus, after the ball hits the floor for the first time, the ball rises to a height of 10 (¨ú ) = 7.5 feet, and after it hits the second floor for the second time, it rises to a height of 7.5 (¨ú ) = 10 (¨ú )©÷ = 5.625 feet.

What happens to the ball when it hits the ground 5 times?

Calculate the total distance travelled by the ball when it hits the ground for the fifth time A ball is dropped from a height of 12 feet and returns to a height that is half the height from which it fell. the ball continues to bounce half the height of its previous bounce each time.

How do you find the total distance travel of a ball?

To find the total distance travel one has to sum over up to n = 3. But there is little subtle point here. For the first bounce ( n = 1 ), the ball has only travel H and not 2H. For subsequent bounces ( n = 2, 3, 4, 5…… ), the distance travel is 2 × ( 3 / 4) n × H This problem can be tackled using geometric progression.

What is the height of the ball after each bounce?

1. A ball is dropped from a height of 10 feet and bounces. Each bounce is [3/4] of the height of the bounce before. Thus after the ball hits the floor for the first time, the ball rises to a height of 10 ( [3/4]) = 7.5 feet, and after the it hits the floor for the second time, the ball rises to a height of 7.5 ( [3/4]) = 10 ( [3/4]) 2 = 5.625 feet.

What is the total distance covered by the ball just before second hit?

The total distance covered by the ball just before the second hit is 11th