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What is the volume of 1 mole of H2 at STP?

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What is the volume of 1 mole of H2 at STP?

22.4 L
As discussed in the previous section, the experiment allows for the determination of pressure, volume, and temperature of H2(g). Avogadro’s law specifies that the volume of one mole of any gas at STP is 22.4 L.

What volume of H2 gas is produced at STP?

The answer is 21.5 L .

What is the volume of 1 mole of gas at STP?

22.41 L/mol
What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure = 0 °C, 1 atm)? So, the volume of an ideal gas is 22.41 L/mol at STP. This, 22.4 L, is probably the most remembered and least useful number in chemistry.

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What volume l of H2 is formed at STP when 6.0 g of Al is treated with excess Naoh?

Now rearrange the equation to solve for the volume. Rounded to two significant figures, the volume of hydrogen gas produced is 7.5 liters.

What is the volume of 2g of h2 at STP?

Hence volume at STP=22.4litres which is the molar volume.

What is STP molar volume?

Standard temperature and pressure (STP) is defined as 0oC (273.15K) and 1atm pressure. The molar volume of a gas is the volume of one mole of a gas at STP. At STP, one mole (6.02×1023 representative particles) of any gas occupies a volume of 22.4L (figure below).

What is the volume of 1 mole of gas at RTP?

24 dm 3
One mole of any gas has a volume of 24 dm 3 or 24,000 cm 3 at rtp (room temperature and pressure). This volume is called the molar volume of a gas.

What is the volume in liters of H2 gas formed at STP when 4.32 g of Al reacts with excess NaOH report your answer to the hundredths place and do not include units?

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Question: What is the volume of H2 gas formed at STP when 4.32g of Al react with excess NaOH? 2 NaOH + 2 Al + 6 H2O —> 2 NaAl(OH)4 + 3 H2I know the answer is 5.38L but I don’t know the step by step formula. Would you like to help me?

What is the volume in l of gaseous H2 produced at STP when 6.32 g of Al reacts with excess NaOH and H2O?

Approx, 8⋅L of dihydrogen gas are evolved.

How to calculate the volume of gas at STP with MG+2HCL?

Mg + 2HCl —> MgCl2 + H2, so each mole Mg makes 1 mole H2 and 0.001268 moles will make 0.001268 moles of H2. This has a volume of 39.9 mL in the experiment. So convert this to stp and then you will know the volume of your gas at stp that contains 0.001268 moles.

What is the volume of hydrogen gas produced when acetic acid reacts with magnesium?

Your volume of hydrogen gas at STP (which is 0 degrees C and I atm) when 1 mole of acetic acid reacts with 1 mole of magnesium is 22.4 litres. Find the number of Mg moles. According to the balanced equation, you can find the moles of H2, which is produced. 25 insanely cool gadgets selling out quickly in 2021.

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What is the volume of CO2 at STP?

Given the number of moles of carbon dioxide, CO 2 = 0.4 mol. Therefore, the volume of CO 2 = number of moles of CO 2 x molar volume at STP. = 0.4 x 22.4 dm 3 = 8.96 dm 3. 2. Find the number of moles of ammonia gas contained in a sample of 60 cm 3 of the gas at room conditions.

How to calculate the volume of gas from moles of MG?

Moles Mg will be 0.0308/24.3 = 0.001268 moles Mg + 2HCl —> MgCl2 + H2, so each mole Mg makes 1 mole H2 and 0.001268 moles will make 0.001268 moles of H2. This has a volume of 39.9 mL in the experiment. So convert this to stp and then you will know the volume of your gas at stp that contains 0.001268 moles.