When a shell is fired at an angle 30 degrees to the horizontal with a velocity 196 m/s What is the horizontal range?

Answer:The maximum height is obtained as 1960m. Hence, 1)The horizontal range is 13579.27m.

How do you find the height of a projectile launched at an angle?

How to find the maximum height of a projectile?

1. if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest.
2. if α = 45°, then the equation may be written as:
3. if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that’s the case of horizontal projectile motion.

What is the angle of projection for a projectile to have maximum range?

45°
Maximum Range: It is the longest distance covered by the object during projectile motion. When the angle of projection is 45°, the maximum range is obtained.

What is the angle of projection at which horizontal range and maximum height equal?

45∘
The angle of projection at which the horizontal range and maximum height of projectile are equal is. 45∘

Why does 45 degrees give maximum range of a projectile?

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

What is the final velocity of a projectile?

The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; its value is 9.8 m/s/s, down, The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.

Why is 45 degrees the best angle for projectile motion?

Originally Answered: Why is 45 degrees the optimal angle for projectiles? It maximizes the projectile’s range (the horizontal distance the projectile travels). Aiming too high causes the projectile to fly higher into the air at a reduced range.

What is the velocity of a shell fired at 30 degrees?

A shell is fired at an angle 30 degree to the horizontal with a velocity 392 m/s. Find the total time of flight horizontal range and maximum height attained? If a shell is projected with an initial velocity of u at an angle θ w.r.t to the horizontal,

How is a shell shot into the air?

During a fireworks display, a shell is shot into the air with an initial speed of 70.0 m/s at an angle of above the horizontal, as illustrated in Figure 3. The fuse is timed to ignite the shell just as it reaches its highest point above the ground. (a) Calculate the height at which the shell explodes.

How to analyze the motion of an unexploded shell?

Because air resistance is negligible for the unexploded shell, the analysis method outlined above can be used. The motion can be broken into horizontal and vertical motions in which and We can then define and to be zero and solve for the desired quantities. By “height” we mean the altitude or vertical position above the starting point.

What happens to the vertical velocity as an object rises?

(c) The velocity in the vertical direction begins to decrease as the object rises; at its highest point, the vertical velocity is zero. As the object falls towards the Earth again, the vertical velocity increases again in magnitude but points in the opposite direction to the initial vertical velocity.